我的代码是正确的,但它看起来太大了。我想知道它是否更高效,变量更少。你有任何提示吗?谢谢你
样本输出
输入三个分数:87 42 94
最低分为:42
没有最低分的平均值是:90.5
等级是:A
<code>
import java.util.Scanner;
public class GradeAverager
{
public static void main(String[] args)
{
int score1,score2,score3;
double average,average_no_lowest;
Scanner keyboard = new Scanner(System.in);
System.out.print("Enter three scores: ");
score1 = keyboard.nextInt();
score2 = keyboard.nextInt();
score3 = keyboard.nextInt();
average = (score1 + score2 + score3) / 3.0;
System.out.println();
System.out.println("The average is: " + average);
if (score1 < score2 && score1 < score3)
System.out.println("The lowest score was:" + score1);
else if (score2 < score1 && score2 < score3)
System.out.println("The lowest score was:" + score2);
else if (score3 < score1 && score3 < score2)
System.out.println("The lowest score was:" + score3);
if (score1 < score2 && score1 < score3){
average_no_lowest = (score2 + score3)/2.0;
System.out.println("The average without the lowest score is: " + average_no_lowest);
if(average_no_lowest > 90)
System.out.print('A');
else if(average_no_lowest < 90 && average_no_lowest > 80 )
System.out.print('B');
else if(average_no_lowest > 70 && average_no_lowest < 80)
System.out.print('C');
else
System.out.print('D');
}
else if (score2 < score1 && score2 < score3){
average_no_lowest = (score1 + score3)/2.0;
System.out.println("The average without the lowest score is: " + average_no_lowest);
if(average_no_lowest > 90)
System.out.print('A');
else if(average_no_lowest < 90 && average_no_lowest > 80 )
System.out.print('B');
else if(average_no_lowest > 70 && average_no_lowest < 80)
System.out.print('C');
else
System.out.print('D');
}
else if (score3 < score1 && score3 < score2){
average_no_lowest =(score1 + score3)/2.0;
System.out.println("The average without the lowest score is: " + (score1 + score3)/2.0);
if(average_no_lowest > 90)
System.out.print('A');
else if(average_no_lowest < 90 && average_no_lowest > 80 )
System.out.print('B');
else if(average_no_lowest > 70 && average_no_lowest < 80)
System.out.print('C');
else
System.out.print('D');
}
}
}
</code>
答案 0 :(得分:5)
您的代码部分为
if(average_no_lowest > 90)
System.out.print('A');
else if(average_no_lowest < 90 && average_no_lowest > 80 )
System.out.print('B');
else if(average_no_lowest > 70 && average_no_lowest < 80)
System.out.print('C');
else
System.out.print('D');
}
重复3次。把它放进一个方法。
在经过验证的问题之前,不要担心性能问题。担心阅读和维护代码是多么容易。
代码有2个受众 - 编译器和人类。人类比编译器更重要。
答案 1 :(得分:0)
将最低分数存储在变量中,例如lowest_score。 并按平均值(总 - 最低分数)/ 2进行平均 这是最有效的
答案 2 :(得分:0)
您可以使用以下代码,这些代码行代码较少,并提供相同的输出::
public static void main(String[] args) {
int score1, score2, score3, status;
double average, average_no_lowest;
Scanner keyboard = new Scanner(System.in);
System.out.print("Enter three scores: ");
score1 = keyboard.nextInt();
score2 = keyboard.nextInt();
score3 = keyboard.nextInt();
average = (score1 + score2 + score3) / 3;
System.out.println("Average Score was:: " + average);
if (score1 < score2 && score1 < score3) {
status = 1;
System.out.println("The lowest score was:: " + score1);
} else if (score2 < score1 && score2 < score3) {
status = 2;
System.out.println("The lowest score was:: " + score2);
} else {
status = 3;
System.out.println("The lowest score was:: " + score3);
}
if (status == 1) {
average_no_lowest = (score2 + score3) / 2;
System.out.println("The average without the lowest score is: "
+ average_no_lowest);
} else if (status == 2) {
average_no_lowest = (score1 + score3) / 2;
System.out.println("The average without the lowest score is: "
+ average_no_lowest);
} else {
average_no_lowest = (score1 + score2) / 2;
System.out.println("The average without the lowest score is: "
+ average_no_lowest);
}
}