Question

如何实例化我的数组，使其中包含26个随机字符？

import java.util.Random; 

public class Encryption {

Random r = new Random();
char[] real = {'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'};
char[] decrypted = //??????

for( i=0; i < decrypted.length; i++) {

}

Answer 1

实例化大小为26的数组;

char[] array = new char[26];

添加随机字符（在小写字母范围内）

for(int i = 0; i < array.length; i++){
     array[i] = (char)(r.nextInt(26) +97);
     System.out.print(array[i]);
}

您可以通过删除随机部分并使用i

来修改此内容以创建第一个数组

for(int i = 0; i < array.length; i++){
     array[i] = (char)(i + 97);
     System.out.print(array[i]);
}

Answer 2

你应该查看这篇文章。它看起来像你正在寻找的答案。 How to generate a random alpha-numeric string?

Answer 3

填写你的例子：

import java.util.Random; 

public class Encryption {

  Random r = new Random();
  char[] real = {'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'};
  char[] decrypted = new char[26];

  public static void main(String[] args){
    for( i=0; i < decrypted.length; i++) {
      decrypted[i] = real[r.nextInt(26)];
    }
  }
}

随机字符生成器存储在数组中

3 个答案: