Question

我的PHP MySQL查询有一个非常奇怪的问题，我正在尝试返回具有正确的rname，rcity和rstate值的行。

$sql = "SELECT * FROM `images` WHERE rname = '" . $rname . "' AND rcity = '" . $rcity . "' AND rstate = '" . $rstate . "'";

当我运行该查询时，它只返回0结果。但是在玩了一些之后，如果我只在WHERE子句中使用rname和rstate它返回结果。

$sql = "SELECT * FROM `images` WHERE rname = '" . $rname . "' AND rstate = '" . $rstate . "';

这很完美。所以当我尝试在WHERE子句中使用rcity时。

$sql = "SELECT * FROM `images` WHERE rcity = '" . $rcity . "'";

0结果返回。所以查询的rcity部分出了问题。如果我将值写入查询而不是$ rcity变量，则会提取结果。我加倍检查以确保声明$ rcity，它具有正确的值等。

我还在数据库中创建了另一个测试表，以检查数据库端是否存在问题。哪个问题仍然存在。

以下是getQuery（）函数的完整代码

private function getQuery($data){
    // Takes raw data and creats image(s) query to search for listing resort...
        $listing = $data['listing'];
        $rname = $data['rname'];
        $rcity = $data['rcity'];
        $rstate = $data['rstate'];

        $query = "SELECT * FROM `test` WHERE rname = '" . $rname . "' AND rcity = '" . $rcity . "' AND rstate = '" . $rstate ."'";

        return $query;
}

这是我的数据库类

class db {

        public function __construct(){
            $this->server = DB_SERVER;
            $this->user = DB_USER;
            $this->Pass = DB_PASS;
            $this->Database = DB_Database;
        }

        protected function connect(){
            return mysqli_connect($this->server, $this->user, $this->Pass, $this->Database);
        }

        public function query($sql){

            $conn = $this->connect();
            $query = $conn->query($sql);

                if($query == false) {
                    throw new Exception("Query failed:".PHP_EOL.$conn->error.PHP_EOL.$sql);
                }
                if($query->num_rows == 0) {
                    // need E_NOTICE errors enabled to see this,
                    // on screen if display_errors is on, else in PHP error log
                    trigger_error("Query returned 0 rows:".PHP_EOL.$sql);
                }
                $result = array();
                    while ($row = $query->fetch_assoc()){
                        $result[] = $row;
                    }
                return $result;
        }

    }

我在类__construct函数中调用查询

$con = new db;

    $sql = $this->getQuery($data);
    $result = $con->query($sql);

Answer 1

我认为问题可以是语法或mysql筛选。尝试使用PDO with bindParam method

Answer 2

$sql = "SELECT * FROM `images` WHERE rname = '$rname' AND rcity = '$rcity' AND rstate = '$rstate'";

尝试实现这一点，即在'（撇号）之间直接使用变量，它应该是完美的

在WHERE子句中使用变量时PHP PHP结果问题

2 个答案: