where子句使用order by来获得结果

Question

SELECT * FROM `fz_users` WHERE `id` in ('6', '1', '30', '34', '11', '3', '2', '7', '4', '24', '221')

我正在使用此查询来显示用户数据和6,1,30 ....是用户的ID但我的问题是我需要按照我给它的相同顺序即6,1 ，30,34,11,3,2

Answer 1

尝试

SELECT * FROM your_table
WHERE id IN ('6', '1', '30', '34', '11', '3', '2', '7', '4', '24', '221')
ORDER BY FIELD(id,'6', '1', '30', '34', '11', '3', '2', '7', '4', '24', '221');