Question

我是Haskell的新手，我正在尝试使用http-conduit版本2.0.0.4的示例代码，但它不起作用

以下是示例代码

{-# LANGUAGE OverloadedStrings #-}
import Network.HTTP.Conduit
import Network
import Data.Time.Clock
import Data.Time.Calendar
import qualified Control.Exception as E

past :: UTCTime
past = UTCTime (ModifiedJulianDay 56200) (secondsToDiffTime 0)

future :: UTCTime
future = UTCTime (ModifiedJulianDay 562000) (secondsToDiffTime 0)

cookie :: Cookie
cookie = Cookie { cookie_name = "password_hash"
               , cookie_value = "abf472c35f8297fbcabf2911230001234fd2"
               , cookie_expiry_time = future
               , cookie_domain = "example.com"
               , cookie_path = "/"
               , cookie_creation_time = past
               , cookie_last_access_time = past
               , cookie_persistent = False
               , cookie_host_only = False
               , cookie_secure_only = False
               , cookie_http_only = False
               }

main = withSocketsDo $ do
    request' <- parseUrl "http://example.com/secret-page"
    let request = request' { cookieJar = Just $ createCookieJar [cookie] }
    E.catch (withManager $ httpLbs request)
            (\(StatusCodeException statusCode _ _) ->
              if statusCode==403 then putStrLn "login failed" else return ())

参考：http://hackage.haskell.org/package/http-conduit-2.0.0.4/docs/Network-HTTP-Conduit.html

加载时的错误消息

samplecode.hs:33:39:
    Couldn't match type `()'
                  with `Response Data.ByteString.Lazy.Internal.ByteString'
    Expected type: IO
                     (Response Data.ByteString.Lazy.Internal.ByteString)
      Actual type: IO ()
    In the return type of a call of `putStrLn'
    In the expression: putStrLn "login failed"
    In the expression:
  if statusCode == 403 then putStrLn "login failed" else return ()

samplecode.hs:33:75:
    Couldn't match expected type `Response
                                    Data.ByteString.Lazy.Internal.ByteString'
                with actual type `()'
    In the first argument of `return', namely `()'
    In the expression: return ()
    In the expression:
      if statusCode == 403 then putStrLn "login failed" else return ()
Failed, modules loaded: none.

我该如何解决？

非常感谢

更新

按照Abrahamson的建议，我已经将我的代码改为以下内容，现在有了正确的StatusCodeException处理。

main = withSocketsDo $ do
    request' <- parseUrl "http://example.com/secret-page"
    let request = request' { cookieJar = Just $ createCookieJar [cookie] }
    eitherResp <- E.try (withManager $ httpLbs request)
    case eitherResp of
      Left (StatusCodeException s _ _) 
        | statusCode s == 403 -> putStrLn "login failed"
        | otherwise         -> return () 
      Right resp -> print (L.length (responseBody resp))

Answer 1

您未按预期使用E.catch。如果你看一下类型：

E.catch :: Exception e => IO a -> (e -> IO a) -> IO a

很清楚第一个和第二个参数的返回类型必须匹配。在你的情况下你有

withManager $ httpLbs request :: IO (Response ByteString)

第一个分支中的

和

putStrLn "login failed" -- or
return ()

在第二个。这些类型不匹配，因此您会收到您看到的错误。

从更高层面来看，问题在于您没有处理成功案例。例如，我们可以使用E.try重写此内容以使其更清晰

eitherResp <- E.try (withManager $ httpLbs request)
case eitherResp of
  Left (StatusCodeException statusCode _ _)
    | statusCode == 403 -> putStrLn "login failed"
    | otherwise         -> return ()
  Right resp -> print (ByteString.length (responseBody resp))

这里因为我在Either StatusCodeException (Response ByteString)上明确地模式匹配，所以我需要提供失败和后续分支，并给它们相同的返回类型。为此，我介绍了一个针对成功案例的行动。

通常，我发现E.try更容易使用。当您想要在失败时提供默认时，E.catch非常有用。

如何在执行http-conduit版本2.0.0.4的示例代码时修复错误

1 个答案: