Question

我正在尝试在textview中显示结果，但是我收到错误。代码是：

private class ContentView extends AsyncTask<String,String,String> {

                    @Override
                    protected void onPreExecute()
                    {   
                        mProgressDialog = new ProgressDialog(SingleActivity.this);
                        mProgressDialog.setTitle("Multiplayer.it");
                        mProgressDialog.setMessage("Caricamento articoli...");
                        mProgressDialog.setIndeterminate(false);
                        mProgressDialog.show();
                        content = new ArrayList<String>();
                    }

                    @Override
                    protected String doInBackground(String... params) {
                        try {
                            //String BLOG_URL_LINKS = links;
                            Document doc = Jsoup.connect(links).get();

                            String info = doc.select("div.col-1-1 article p").text();


                            System.out.println(info);
                            //info.toString();




                        } catch (Exception e) {
                            // In caso di errore

                            Log.e("ESEMPIO", "ERRORE NEL PARSING");
                        }
                        return null;
                    }


                    @Override
                    protected void onPostExecute(String result)
                    {   
                        articololink = (TextView)findViewById(R.id.content);
                        articololink.setText(info);
                        mProgressDialog.dismiss();
                    }


                }

问题是：info cannot be resolved to a variable。我该怎么办？

Answer 1

在doInbackground中声明和初始化信息是doInbackground的本地信息。

所以在info

中返回doInbackground

 @Override
 protected String doInBackground(String... params) {
      String info=null;
      try {
          Document doc = Jsoup.connect(links).get();
          info = doc.select("div.col-1-1 article p").text();
         } catch (Exception e) {
             e.printStacktrace();     
         }
    return info;
 }

然后在onPostExecute

   @Override
   protected void onPostExecute(String result)
   {  
            super.onPostExecute(result);    
            articololink = (TextView)findViewById(R.id.content);
            articololink.setText(result);
            mProgressDialog.dismiss();
    }

请阅读 4个步骤 @

主题

http://developer.android.com/reference/android/os/AsyncTask.html

onPostExecute（）中的语法错误

1 个答案: