AsyncTask onPostExecute - 新的意图错误

Question

我在AsyncTask类中有这个代码：

    protected void onPostExecute(Integer result) 
    {
        if (result == 1)
        {
            try {
                Global.mmOutStream.write(99);
            } catch (IOException e) { }

            Intent intentTrashcanLocation = new Intent(TrashcanLocationActivity.this, TrashcanLocationActivity.class);     
            startActivity(intentTrashcanLocation);
        }

    }

这让我在＆＃34; Intent＆＃34;行：

• 行断点：TrashcanOnWayActiity$waitarrival [line:53] - onPostExecute(Integer)
• 在范围
中无法访问类型TrashcanLocationActivity的封闭实例

我想要做的是基本上每当我异步获得某些输入时显示下一页。我无法解决这个问题。任何帮助将非常感谢！

Answer 1

您正在使用相同的课程

Intent intentTrashcanLocation = new Intent(TrashcanLocationActivity.this,
                                           TrashcanLocationActivity.class);     
startActivity(intentTrashcanLocation);

应该是一致的

Intent intentTrashcanLocation = new Intent(TrashcanLocationActivity.this,
                                           TrashcandetailActivity.class);     
startActivity(intentTrashcanLocation);

Answer 2

试试这个，

        @Override
            protected void onPostExecute(Void result) 
           {
               super.onPostExecute(result);
               if (result == 1)
               {
                try {
                    Global.mmOutStream.write(99);
                    } catch (IOException e) { }

               Intent intent = new Intent(TrashcanLocationActivity.this, NextActivity.class); 
               getApplicationContext().startActivity(intent);
              }
           }

Answer 3

您的代码没问题，但您再次调用相同的活动

 Intent intentTrashcanLocation = new Intent(TrashcanLocationActivity.this, TrashcanLocationActivity.class);     
            startActivity(intentTrashcanLocation);

将TrashcanLocationActivity.class替换为您要调用的活动.class