Question

问题： 我有一个案例，每当句子中的单词发生变化时，我需要用dc替换句子中的单词。这句话是：

Sweet Bad No No Long Yes Bike No Yes

在接下来的几次中，这句话将继续改为：

Sweet Bad No No Long Yes Bike Yes No

Sweet Bad No No Short Yes Car Yes No

因此，输出应如下所示：

Sweet Bad No No dc Yes dc dc dc

我想用dc替换第一个更改的实例，从第一个句子到下一个句子。我写了一段代码，但似乎不对。我哪里错了？

 dont_care = "dc"
 hyp_curr = []
 hyp_next = []

 def create_hypothesis(stVal):
      splitVal = stVal.split()
      global hyp_curr
      global hyp_next

      if not hyp_curr: 
           hyp_curr = (' '.join(w for w in splitVal if w not in hyp_curr))
           return hyp_curr
      else: 
           hyp_next = splitVal
           print hyp_curr
           print hyp_next

           for wordc in hyp_curr.split():
                for wordn in hyp_next:
                     if hash(wordc) != hash(wordn):
                          hyp_curr = hyp_curr.replace(wordn,dont_care)
                          return hyp_curr

Answer 1

>>> s = "Sweet Bad No No Long Yes Bike No Yes"
>>> s1 = "Sweet Bad No No Long Yes Bike Yes No"
>>> map(lambda x: x[0]==x[1] and x[0] or 'dc', zip(s.split(), s1.split()))
['Sweet', 'Bad', 'No', 'No', 'Long', 'Yes', 'Bike', 'dc', 'dc']
>>> ' '.join(_)
'Sweet Bad No No Long Yes Bike dc dc'

或：

>>> [x[0]==x[1] and x[0] or 'dc' for x in zip(s.split(), s1.split())]
['Sweet', 'Bad', 'No', 'No', 'Long', 'Yes', 'Bike', 'dc', 'dc']

Answer 2

也许是这样的？

#!/usr/local/cpython-3.3/bin/python

import pprint

def rep_dc(list_):
    result = []
    for sublist1, sublist2 in zip(list_[:-1], list_[1:]):
        assert len(sublist1) == len(sublist2)
    for tuple_ in zip(*list_):
        set_ = set(tuple_)
        if len(set_) > 1:
            result.append('dc')
        else:
            result.append(tuple_[0])
    return result

def main():
    list1 = 'Sweet Bad No No Long Yes Bike No Yes'.split()
    list2 = 'Sweet Bad No No Long Yes Bike Yes No'.split()
    list3 = 'Sweet Bad No No Short Yes Car Yes No'.split()

    master_list = [ list1, list2, list3 ]
    pprint.pprint(master_list)
    result = rep_dc(master_list)
    print(result)
    result_string = ' '.join(result)
    print(result_string)

main()

Python - 多次替换一个单词

2 个答案: