Question

基本上，有一群20只羊。在该群体成长为80只绵羊后，该群体不再需要受到监督。羊的数量N，每年，每年，t，见：

N = 220 /（1 + 10（0.83）^ t）

这个程序试图找出绵羊必须监督多少年，然后从零开始写出N的值，从零开始，直到25。

到目前为止这是我的代码......它似乎不起作用，我知道有关与权力相乘的部分有关。我试图使用一个变量“power”，在循环的每次迭代中乘以0.83。感谢任何帮助，谢谢。

   public static void main(String[] args) {

    System.out.println("A breeding group of 20 bighorn sheep is released in a protected area in Colorado.");
    System.out.println("After the group has reached a size of 80 sheep, the group does not need to be supervised anymore.");
    System.out.println("This program calculates how many years the sheep have to be supervised.");
    int number = 20;
    int power = 1;
    for(int years = 0; number < 80; power*= 0.83) {
        number = 220 / (1 + 10 * power);           
        System.out.println("After " + years + " years, the number of sheep is: " + number);
        years++;
    }
}
 }

Answer 1

将数字和功率的数据类型从int更改为double。我试了一下，它运行正常。您也可能希望修改for循环以在多年时间内运行＆lt; 25而不是数字＆lt; 80.并将数字作为循环内的局部变量以保持清洁。

public static void main(String[] args) {
    System.out.println("A breeding group of 20 bighorn sheep is released in a protected area in Colorado.");
    System.out.println("After the group has reached a size of 80 sheep, the group does not need to be supervised anymore.");
    System.out.println("This program calculates how many years the sheep have to be supervised.");
    double power = 1;
    boolean foundFirstOverEighty = false;
    for (int years = 0; years < 25; years++) {
        double number = 220 / (1 + 10 * power);
        System.out.println("After " + years + " years, the number of sheep is: " + number);

        if (!foundFirstOverEighty && number >= 80) {
            System.out.println("First time number of sheep exceeded eighty. " + years + " years. number of sheep is: " + number);
            foundFirstOverEighty = true;
        }

        power *= 0.83;
    }
}

for Java in Java - exponents

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