我在使用这段代码时遇到了很多麻烦。作业是:
您要编写一个程序来处理员工及其薪酬。对于每个员工,该计划将读取员工的姓名和每小时工资率。它还应该读取每天工作5小时的工作小时数并计算他或她的总工作小时数。您必须使用循环读取小时数。该计划应输出员工姓名,工资总额,扣缴总额和净工资。“ 预扣税由州税,联邦税和FICA组成。就本计划而言,州税是总薪酬的1.25%。 FICA将占总薪酬的7.65%。如果总薪酬低于500美元,则联邦税将为总薪酬的15%,否则为25% 您不知道有多少员工,但会有员工姓名的哨兵。哨兵是“完成”
但是代码编译输出总是很大的指数。谢谢你的任何建议。
#include<iostream>
#include<string>
#include<iomanip>
using namespace std;
void instructions(string &name, float &rate, float &sum);
string getName();
float getRate();
float getHours();
float calcPay(float rate, float sum);
float calcGross(float pay);
float calcAmount(float gross);
float calcNet(float gross, float with);
void output(string name, float rate, float sum, float with, float gross, float net, float\
pay);
int main()
{
string name, done;
int counter;
float rate, sum, gross, with, pay, net;
instructions(name, rate, sum);
calcPay(rate, sum);
output(name, rate, sum, with, gross, net, pay);
return 0;
}
void instructions(string &name, float &rate, float &sum)
{
name = getName();
rate = getRate();
sum = getHours();
}
string getName()
{
string name, done;
cout<<"Enter the name of the employee: "<<" ";
cin>>name;
if (name == done)
{
cout <<"bye!";
}
return name;
}
float getRate()
{
float rate;
cout<<"Enter the hourly pay rate: "<<" ";
cin>>rate;
return rate;
}
float getHours()
{
int counter;
float hours, sum=0;
for (counter=1; counter <=5; counter++)
{
cout<<"Enter the number of hours worked for Day "<<counter<<":"<<" ";
cin>> hours;
sum += hours;
}
return sum;
}
float calcPay(float rate, float sum)
{
float pay;
pay = rate * sum;
return pay;
}
float calcGross (float pay)
{
float gross;
gross = (pay * .89);
return gross;
}
float calcAmount(float gross)
{
float with;
if (gross >500)
with = (gross *.15);
else
with = (gross *.25);
return with;
}
float calcNet(float gross, float with)
{
float net;
net = gross - with;
return net;
}
void output(string name, float rate, float sum, float with, float gross, float net, float\
pay)
{
gross = calcGross(pay);
with = calcAmount(gross);
net = calcNet(gross, with);
cout<<"Payroll"<<'\n';
cout<<"======================================="<<'\n';
cout<<"Employee name: "<<name<<'\n';
cout<<"Gross pay: $ "<<setprecision(2)<<gross<<'\n';
cout<<"Total Withholding: $ "<<setprecision(2)<<with<<'\n';
cout<<"Net pay: $ "<<setprecision(2)<<net<<'\n';
}
示例运行:
Enter the name of the employee: Alice
Enter the hourly pay rate: 7.75
Enter the number of hours worked for Day 1: 5
Enter the number of hours worked for Day 2: 6
Enter the number of hours worked for Day 3: 5
Enter the number of hours worked for Day 4: 4
Enter the number of hours worked for Day 5: 5
Payroll
=======================================
Employee name: Alice
Gross pay: $ -1.9e+38
Total Withholding: $ -4.8e+37
Net pay: $ -1.4e+38
答案 0 :(得分:1)
您似乎没有初始化“付款”的值。
我错过了你初始化的地方吗?
也许你的意思是:
pay = calcPay(rate, sum);
等
另外:如果你在输出(...)中计算“with”,“gross”和“net”,你可能不应该将它们作为未初始化的变量传递。你是说他们出来(例如参考)还是他们在之前被初始化了?
答案 1 :(得分:0)
在代码变量pay
中,gross
,
和pay
pay
未初始化。由于上面的代码,它将是这样的:
net
输出给出指数,因为在代码中明确放置了int main()
{
string name, done;
int counter;
float rate, sum, gross, with, pay, net;
instructions(name, rate, sum);
pay = calcPay(rate, sum);
gross = calcGross(pay);
with = calcAmount(gross);
net = calcNet(gross, with);
output(name, rate, sum, with, gross, net, pay);
return 0;
}
。由于人类可读性,我在下面的代码中省略了精度:
<<setprecision(2)
答案 2 :(得分:0)
您忘记在main函数中初始化变量。 只需像这样修改你的程序,它就可以运行。
int main()
{
string name, done;
int counter;
float rate, sum, gross, with, pay, net;
instructions(name, rate, sum);
pay=calcPay(rate, sum);
output(name, rate, sum, with, gross, net, pay);
return 0;
}
void output(string name, float rate, float sum, float& with, float& gross, float& net, float& pay)
{
gross = calcGross(pay);
with = calcAmount(gross);
net = calcNet(gross, with);
cout<<"Payroll"<<'\n';
cout<<"======================================="<<'\n';
cout<<"Employee name: "<<name<<'\n';
cout<<"Gross pay: $ "<<gross<<'\n';
cout<<"Total Withholding: $ "<<with<<'\n';
cout<<"Net pay: $ "<<net<<'\n';
}