我要求在Struts2-Jquery Grid
中实施一列
像贝娄一样
------------------------------
col1 | col2 is main column
________|________________________
| Sub col1 | Sub col 2
________|___________|____________
/* Data */ in rows format
我和我想在子列中添加Tick
符号。可以任何人请帮助我如何实现这一目标
我正在使用Struts2 Jquery grid
以下是我的JSP页面请告诉我我在做错误的地方。
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN""http://www.w3.org/TR/html4/loose.dtd">
<%@page contentType="text/html" pageEncoding="UTF-8"%>
<%@ taglib prefix="s" uri="/struts-tags"%>
<%@ taglib prefix="sj" uri="/struts-jquery-tags"%>
<%@ taglib prefix="sjg" uri="/struts-jquery-grid-tags"%>
<html>
<head>
<sj:head jquerytheme="redmond" jqueryui="true" />
<title>JSP Page</title>
<script type="text/javascript">
function doGridComplete()
{
$("#gridId").jqGrid('setGroupHeaders', { useColSpanStyle: true, groupHeaders:[ {startColumnName: 'idcountry', numberOfColumns: 2, titleText: '<em>col2 is main column</em>'}] }).trigger("reloadGrid");
}
</script>
</head>
<body>
<s:form name="testform" >
<s:url id="topgrid" action="countrygrid"/>
<s:url id="middlegrid" action="stategrid"/>
<s:url id="bottomgrid" action="citygrid"/>
<sjg:grid dataType="json" gridModel="gridModel" navigator="false"
pager="true"
viewrecords="true" width="600"
href="%{topgrid}"
height="400"
id="gridId"
>
<sjg:gridColumn name="idcountry" title="Country Id" labelSeparator="jak" label="HI this is lable">
</sjg:gridColumn>
<sjg:gridColumn name="countryname" disabled="true" title="Country Name" key="true" align="center"/>
<sjg:gridColumn name="countryname" title="Country Name" key="true" align="center"/>
<sjg:gridColumn name="countryname" title="Country Name" key="true" align="center"/>
<sjg:gridColumn name="countryname" title="Country Name" key="true" align="center"/>
</sjg:grid>
<script language='JavaScript' type='text/JavaScript'>
function doGridComplete()
{
$("#gridId").jqGrid('setGroupHeaders', { useColSpanStyle: true, groupHeaders:[ {startColumnName: 'idcountry', numberOfColumns: 2, titleText: '<em>col2 is main column</em>'}] }).trigger("reloadGrid");
}
doGridComplete();
</script>
</s:form>
</body>
</html>
答案 0 :(得分:2)
在网格后调用doGridComplete()
。
<sjg:grid dataType="json" gridModel="gridModel" navigator="false"
pager="true"
viewrecords="true" width="600"
href="%{topgrid}"
height="400"
id="gridId"
onGridCompleteTopics="gridcomplete">
<sjg:gridColumn name="idcountry" title="Country Id" labelSeparator="jak" label="HI this is lable">
</sjg:gridColumn>
<sjg:gridColumn name="countryname" title="Country Name" key="true" align="center"/>
</sjg:grid>
<script language='JavaScript' type='text/JavaScript'>
function doGridComplete()
{
$("#gridId").jqGrid('setGroupHeaders', { useColSpanStyle: true, groupHeaders:[ {startColumnName: 'sub_Col1_name', numberOfColumns: 2, titleText: '<em>col2 is main column</em>'}] });
}
doGridComplete();
</script>
sub_Col1_name
中的 startColumnName
是要从中开始标题分组的列的名称。希望这会有所帮助。