我的游戏Master Mind的循环有什么问题？ （JavaScript的）

Question

我正在尝试制作Master Mind的javascript / html游戏。 （规则在这里） http://en.wikipedia.org/wiki/Mastermind_%28board_game%29

基本上，用户隐藏了4种颜色。用户试图猜测颜色。该程序将只返回以下信息。

1）正确位置的正确颜色数量。

2）错误位置的正确颜色数量。

3）颜色不正确的数量。

我希望代码为每个正确的答案创建一个红色圆圈，为每个正确的颜色创建白色，但是不正确的地方，以及错误答案的灰色。
我觉得我的逻辑是正确的，但程序不断吐出不正确的数据。我觉得我错过了什么。 任何帮助都是极好的。

var guessedAlready = [4];
var correctAlready = [4];
for(var i = 0; i<4; i++)                                   //set array to see if answer was already guessed
    {
correctAlready[i] = 0;
guessedAlready[i] = 0;  
     }  
for(var i = 0; i<4; i++)
{
if(color1 == answerArray [i])
{
    if(i == 0)
    {
        correctAnswer += 1; 

    guessedAlready[i] = 1;
    }
    if (guessedAlready[i] != 1)
    {
        incorrectPlace +=1;
    }

    guessedAlready[i] = 1;
}

if(color2 == answerArray [i])
{
    if(i == 1)
    {
        correctAnswer+=1;

        if(guessedAlready[i] == 1)
        {
        incorrectPlace -= 1;
        }
    }

    if (guessedAlready[i] != 1)
    {
        incorrectPlace +=1;
    }
    guessedAlready[i]=1;
}
if(color3 == answerArray [i])
{
    if(i == 2)
    {
        correctAnswer+=1;

        if(guessedAlready[i] == 1)
        {
        incorrectPlace -= 1;
        }
    }

    if (guessedAlready[i] != 1)
    {
        incorrectPlace +=1;
    }
    guessedAlready[i]=1;
}
if(color4 == answerArray [i])
{
    if(i == 3)
    {
        correctAnswer += 1; 
        if(guessedAlready[i] == 1)
            {
            incorrectPlace -=1;
            }
    }

    if (guessedAlready[i] != 1)
    {       
        incorrectPlace +=1;
    }
    guessedAlready[i]=1;
}
 }


 wrongAnswer = 4-incorrectPlace-correctAnswer;
 //---------------------------------------------------------------creates divs for each correct, incorrectly placed, and wrong answer---------------//
 for(var i = 0; i<correctAnswer; i++)
 {
var myElement = document.createElement('div');
myElement.className = 'pastAnswerShow';
myElement.id = 'answerShow'+tracker;
pastAnswerBox.appendChild(myElement);
myElement.style.background = 'black';
keyTracker+=1;
 }

 for(var i = 0; i <incorrectPlace; i++)
 {
var myElement = document.createElement('div');
myElement.className = 'pastAnswerShow';
myElement.id = 'answerShow'+tracker;
pastAnswerBox.appendChild(myElement);
myElement.style.background = 'white';
keyTracker+=1;
 }

 for(var i = 0; i<wrongAnswer; i++)
 {  
var myElement = document.createElement('div');
myElement.className = 'pastAnswerShow';
myElement.id = 'answerShow'+tracker;
pastAnswerBox.appendChild(myElement);
myElement.style.background = 'grey';
keyTracker+=1;
 }

Answer 1

你有第一个，但你需要添加

guessedAlready[i]=1;

如果i = 1，则i = 2且i = 3，如下所示：

if(i == 3)
{
    correctAnswer += 1; 
    if(guessedAlready[i] == 1)
    {
        incorrectPlace -=1;
    }
    guessedAlready[i]=1;
}

那应该解决你的逻辑问题