所以我试图"优化"我的代码,通过使用大量循环减少行数。但它有问题。
我只是试图显示一堆单选按钮,只显示两个按钮而且都没有做任何事情。
只是想知道是否有人可以批评我的代码,并在他出错的地方显示这个新内容。
感谢任何帮助:)
import java.awt.event.*;
import javax.swing.*;
import javax.swing.JOptionPane;
import javax.swing.JFrame;
import javax.swing.JLabel;
import java.awt.BorderLayout;
import java.awt.Color;
public class NewGame implements ActionListener {
private final String[] premierLeagueClubs = {"Arsenal", "Bournemouth", "Burnley", "Chelsea", "Crystal Palace",
"Everton", "Hull City", "Leicester City", "Liverpool", "Manchester United", "Manchester City", "Middlesborough",
"Southampton", "Stoke City", "Sunderland", "Swansea City", "Tottenham Hotspur", "Watford", "West Brom", "West Ham"};
private final JRadioButton[] rb = new JRadioButton[20];
JFrame f3;
private final JButton b, quit;
String teamName;
JLabel label1;
private static JPanel chooseClubPanel;
public NewGame() {
f3 = new JFrame("Ballon d'or");
f3.setExtendedState(JFrame.MAXIMIZED_BOTH);
f3.setDefaultCloseOperation(WindowConstants.DO_NOTHING_ON_CLOSE);
chooseClubPanel = new JPanel();
f3.add(chooseClubPanel, BorderLayout.CENTER);
chooseClubPanel.setBackground(Color.GREEN);
label1 = new JLabel("Please choose a team");
chooseClubPanel.add(label1);
ButtonGroup bg = new ButtonGroup();
int startvalueBG;
int endvalueBG = 19;
for (startvalueBG = 0; startvalueBG <= endvalueBG; startvalueBG++) {
bg.add(rb[startvalueBG]);
}
b = new JButton("OK");
b.addActionListener(this);
chooseClubPanel.add(b);
quit = new JButton("Quit");
quit.addActionListener(this);
chooseClubPanel.add(quit);
int startValueAddRB;
int endValueAddRB = 19;
for (startValueAddRB = 0; startValueAddRB <= endValueAddRB; startValueAddRB++) {
f3.add(rb[startValueAddRB]);
}
int startRB;
int endRB = 19;
for (startRB = 0; endRB <= 19; startRB++) {
for (int i = 0; i < premierLeagueClubs.length; i++) {
rb[startRB] = new JRadioButton(premierLeagueClubs[i]);
chooseClubPanel.add(rb[i]);
}
}
f3.addWindowListener(new WindowAdapter() {
@Override
public void windowClosing(WindowEvent e) {
if (JOptionPane.showConfirmDialog(f3, "Are you sure ?", "Warning", JOptionPane.YES_NO_OPTION) == JOptionPane.YES_OPTION) {
f3.setVisible(false);
f3.dispose();
} else {
f3.setVisible(true);
}
}
});
}
public void setFrame(JFrame f3) {
this.f3 = f3;
}
public JFrame getFrame() {
return f3;
}
@Override
public void actionPerformed(ActionEvent e) {
int rbNumber;
int rbNumberMax = 19;
for (rbNumber = 0; rbNumber < rbNumberMax; rbNumber++) {
if (rb[rbNumber].isSelected()) {
teamName = rb[rbNumber].getText();
f3.dispose();
JOptionPane.showMessageDialog(f3, "You chose : " + rb[rbNumber].getText());
}
}
}
}
答案 0 :(得分:1)
所以,让我们来看看代码......
首先,您尝试将每个按钮添加到ButtonGroup
,但是,您还没有实际创建任何按钮,可能NullPointerException
int startvalueBG;
int endvalueBG = 19;
for (startvalueBG = 0; startvalueBG <= endvalueBG; startvalueBG++) {
bg.add(rb[startvalueBG]);
}
b = new JButton("OK");
b.addActionListener(this);
chooseClubPanel.add(b);
quit = new JButton("Quit");
quit.addActionListener(this);
chooseClubPanel.add(quit);
然后你将每个按钮添加到框架中,但框架使用BorderLayout
,因此只有一个按钮可见,最后一个按钮...
int startValueAddRB;
int endValueAddRB = 19;
for (startValueAddRB = 0; startValueAddRB <= endValueAddRB; startValueAddRB++) {
f3.add(rb[startValueAddRB]);
}
然后你尝试将按钮添加到chooseClubPanel
,有效地从框架中移除,但索引全部搞砸了,你正在创建19x19按钮,每个俱乐部分配给所有19个并且有效地替换为下一个俱乐部......!?!?
int startRB;
int endRB = 19;
for (startRB = 0; endRB <= 19; startRB++) {
for (int i = 0; i < premierLeagueClubs.length; i++) {
rb[startRB] = new JRadioButton(premierLeagueClubs[i]);
chooseClubPanel.add(rb[i]);
}
}
我们要做的第一件事就是删除对chooseClubPanel
框架的引用,它们只是妨碍了,并且该类没有业务生成框架,&#39不是它的责任。
接下来,我们将NewGame
设为JPanel
并允许其自行管理。
接下来,我们将把循环次数从3减少到1并完成我们需要同时完成的所有工作
public class NewGame extends JPanel implements ActionListener {
private final String[] premierLeagueClubs = {"Arsenal", "Bournemouth", "Burnley", "Chelsea", "Crystal Palace",
"Everton", "Hull City", "Leicester City", "Liverpool", "Manchester United", "Manchester City", "Middlesborough",
"Southampton", "Stoke City", "Sunderland", "Swansea City", "Tottenham Hotspur", "Watford", "West Brom", "West Ham"};
private final JRadioButton[] rb = new JRadioButton[20];
private final JButton b, quit;
String teamName;
JLabel label1;
ButtonGroup bg = new ButtonGroup();
public NewGame() {
setBackground(Color.GREEN);
label1 = new JLabel("Please choose a team");
add(label1);
for (int i = 0; i < premierLeagueClubs.length; i++) {
rb[i] = new JRadioButton(premierLeagueClubs[i]);
rb[i].setActionCommand(premierLeagueClubs[i]);
bg.add(rb[i]);
add(rb[i]);
}
b = new JButton("OK");
b.addActionListener(this);
add(b);
quit = new JButton("Quit");
quit.addActionListener(this);
add(quit);
}
@Override
public void actionPerformed(ActionEvent e) {
System.out.println("You have selected " + bg.getSelection().getActionCommand());
}
}
在某些时候,您想要显示,最简单的解决方案是将其添加到您想要的任何容器中,例如JFrame
public static void main(String[] args) {
SwingUtilities.invokeLater(new Runnable() {
@Override
public void run() {
JFrame frame = new JFrame("Title");
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
frame.add(new NewGame());
frame.pack();
frame.setLocationRelativeTo(null);
frame.setVisible(true);
}
});
}
通常情况下,我建议您查看Laying Out Components Within a Container,但在您的情况下,我认为查看How to Use Lists
会更为实际