Question

有没有办法显示sql server agent job的状态/输出？

我有一个运行实际运行SQL Server代理作业的存储过程的应用程序（参见下文），但有没有办法显示正在运行的作业的状态？如果作业失败，我可以通过直接进入SQL Server Studio并查看作业的历史记录进行检查，但无法从应用程序中判断出来。

理想情况下，我希望能够在应用程序中显示类似的内容：

Executing job...
Starting Step 1... Success
Starting Step 2... Success

但如果有人知道如何显示

Job Ran Successfully或Job Failed. Error Message..

这是我当前运行存储过程的代码

感谢任何帮助，想法，建议从哪里开始

 Sub btnImport_click(ByVal sender As Object, ByVal e As EventArgs)

    Dim sqlConnection1 As New SqlConnection("CONNECTION STRING")
    Dim cmd As New SqlCommand
    Dim rowsAffected As Integer
    cmd.CommandText = "dbo.runImportDGDataJob"
    cmd.CommandType = CommandType.StoredProcedure
    cmd.Connection = sqlConnection1
    sqlConnection1.Open()
    rowsAffected = cmd.ExecuteNonQuery()
    sqlConnection1.Close()
End Sub

Answer 1

这是我的答案。 Default.aspx：

<%@ Page Title="Home Page" Language="VB" MasterPageFile="~/Site.Master" AutoEventWireup="true" CodeBehind="Default.aspx.vb" Inherits="LaunchJobAndWaitTillDone_VB._Default" %>

<asp:Content ID="BodyContent" ContentPlaceHolderID="MainContent" runat="server">

    <div class="jumbotron">
        <h1>Launch Job And Wait Till Done (VB)</h1>
        <p class="lead">Launch SQL Server Agent Job, wait for it to finish, then display the result (VB.NET version)</p>
    </div>

    <div class="row">
        <div class="col-md-4">
            <asp:Button ID="btnImport" runat="server" Text="Import" />
        </div>
        <div class="col-md-4">
            <asp:Label ID="lblOutput" runat="server" Text=""></asp:Label>
        </div>
    </div>

</asp:Content>

...和Default.aspx.vb：

Imports System
Imports System.Data
Imports System.Data.SqlClient

Public Class _Default
    Inherits Page

    Const ConnectionString As String = "Data Source=YOURSERVERNAMEHERE;Initial Catalog=msdb;Integrated Security=SSPI"
    Const JobName As String = "YOURJOBNAMEHERE"
    Shared ReadOnly WaitFor As TimeSpan = TimeSpan.FromSeconds(1.0)

    Enum JobExecutionResult
        Succeeded
        FailedToStart
        FailedAfterStart
        Unknown
    End Enum

    Protected Sub Page_Load(ByVal sender As Object, ByVal e As EventArgs) Handles Me.Load

    End Sub

    Private Sub btnImport_Click(sender As Object, e As EventArgs) Handles btnImport.Click
        Dim JobResult As JobExecutionResult = RunJob(JobName)

        Select Case JobResult
            Case JobExecutionResult.Succeeded
                lblOutput.Text = $"SQL Server Agent job, '{JobName}', ran successfully to completion."
            Case JobExecutionResult.FailedToStart
                lblOutput.Text = $"SQL Server Agent job, '{JobName}', failed to start."
            Case JobExecutionResult.FailedAfterStart
                lblOutput.Text = $"SQL Server Agent job, '{JobName}', started successfully, but encountered an error."
            Case Else
                lblOutput.Text = $"Unknown result from attempting to run SQL Server Agent job, '{JobName}'."
        End Select
    End Sub

    Function RunJob(ByVal JobName As String) As JobExecutionResult
        Dim JobResult As Integer

        Using JobConnection As SqlConnection = New SqlConnection(ConnectionString)
            Dim JobCommand As SqlCommand
            Dim JobReturnValue As SqlParameter
            Dim JobParameter As SqlParameter

            JobCommand = New SqlCommand("sp_start_job", JobConnection)
            JobCommand.CommandType = CommandType.StoredProcedure

            JobReturnValue = New SqlParameter("@RETURN_VALUE", SqlDbType.Int)
            JobReturnValue.Direction = ParameterDirection.ReturnValue
            JobCommand.Parameters.Add(JobReturnValue)

            JobParameter = New SqlParameter("@job_name", SqlDbType.VarChar)
            JobParameter.Direction = ParameterDirection.Input
            JobCommand.Parameters.Add(JobParameter)
            JobParameter.Value = JobName

            JobConnection.Open()
            Try
                JobCommand.ExecuteNonQuery()
                JobResult = CInt(JobCommand.Parameters("@RETURN_VALUE").Value)
            Catch ex As SqlException
                JobResult = -1
            End Try
        End Using

        If JobResult <> 0 Then
            Return JobExecutionResult.FailedToStart
        End If

        While True
            Using JobConnection2 As SqlConnection = New SqlConnection(ConnectionString)
                Dim JobCommand2 As SqlCommand = New SqlCommand("sp_help_jobactivity", JobConnection2)
                JobCommand2.CommandType = CommandType.StoredProcedure

                Dim JobReturnValue2 As SqlParameter = New SqlParameter("@RETURN_VALUE", SqlDbType.Int)
                JobReturnValue2.Direction = ParameterDirection.ReturnValue
                JobCommand2.Parameters.Add(JobReturnValue2)

                Dim JobParameter2 As SqlParameter = New SqlParameter("@job_name", SqlDbType.VarChar)
                JobParameter2.Direction = ParameterDirection.Input
                JobCommand2.Parameters.Add(JobParameter2)
                JobParameter2.Value = JobName

                JobConnection2.Open()
                Dim rdr As SqlDataReader = JobCommand2.ExecuteReader()
                While rdr.Read()
                    Dim Msg As Object = rdr("message")
                    Dim Run_Status As Object = rdr("run_status")
                    If Not IsDBNull(Msg) Then
                        Dim Message As String = TryCast(Msg, String)
                        Dim RunStatus As Integer? = Run_Status
                        If Message IsNot Nothing AndAlso Message.StartsWith("The job succeeded") _
                            AndAlso RunStatus.HasValue AndAlso RunStatus.Value = 1 Then
                            Return JobExecutionResult.Succeeded
                        ElseIf Message IsNot Nothing AndAlso Message.StartsWith("The job failed") Then
                            Return JobExecutionResult.FailedAfterStart
                        ElseIf RunStatus.HasValue AndAlso RunStatus.Value = 1 Then
                            Return JobExecutionResult.Unknown
                        End If
                    End If
                End While
            End Using

            System.Threading.Thread.Sleep(WaitFor)
        End While
    End Function
End Class

请注意，此解决方案是同步：在SQL Server代理作业完成之前，回发不会返回。如果有人有更好的解决方案，请随时发布。

在Web应用程序中显示sql server agent作业的状态/输出

1 个答案: