我尝试使用MSVS2012,CUDA5.5,Thrust 1.7编译此代码:
#include <iostream>
#include <thrust/iterator/counting_iterator.h>
#include <thrust/iterator/transform_iterator.h>
#include <thrust/find.h>
#include <thrust/execution_policy.h>
struct is_odd {
__host__ __device__ bool operator()(uint64_t &x) {
return x & 1;
}
};
int main() {
thrust::counting_iterator<uint64_t> first(0);
thrust::counting_iterator<uint64_t> last = first + 100;
auto iter = thrust::find(thrust::device,
thrust::make_transform_iterator(first, is_odd()),
thrust::make_transform_iterator(last, is_odd()),
true);
int bbb; std::cin >> bbb;
return 0;
}
并收到错误:
错误1错误:不允许不完整类型C:\ Program Files \ NVIDIA GPU Computing Toolkit \ CUDA \ v5.5 \ include \ thrust \ detail \ type_traits.h 413 1 HostDevice
如果我使用host / device_vector而不是counting_iterator那么一切都好。怎么了?
答案 0 :(得分:4)
我稍微改变了你的算子定义:
struct is_odd {
__host__ __device__ bool operator()(uint64_t &x) {
到此:
struct is_odd : public thrust::unary_function<uint64_t, bool> {
__host__ __device__ bool operator()(const uint64_t &x) {
它为我编译。