Question

在Python 2.7中使用argparse我试图通过不重复代码和使用代码进行重用来减少我的代码。在这种情况下，我试图重用给予不同子分析器的参数。但是，我收到的错误可能与我试图调用/分配属性的方式有关：

import argparse

def create_args():
    parser = argparse.ArgumentParser(description='Transfer file between accounts.'
                                                  'Add/remove tabs and Schemas')
    subparser = parser.add_subparsers(help='Transfer file between acconts')
    transfer = subparser.add_parser('transfer', 
                                     help="Transfer file from 2 accounts")

    add_arguments(transfer, "producer", "consumer",  "uuid")

    return parser


def add_arguments(group, *args):
    options = group.add_argument_group("Switches")

    choices = {  
            "producer" : ('-p',
                          '--producer',
                          'required=True',
                          'help="Producer\'s(source account)"'),
             "consumer" : ('-c',
                           '--consumer',
                           'required=True',
                           'help="Consumer\'s(destination account)"'),
                 "uuid" : ('-u', 
                           '--uuid',
                           'required=True',
                           'help="file ID number"')}
    for arg in args:
        options.add_argument(choices[arg])

   one@dash ~/image_transfer $ python transfer.py transfer
    Traceback (most recent call last):
      File "transfer.py", line 19, in <module>
        start()
      File "transfer.py", line 12, in start
        args = vars(parser.parse_args())
      File "/usr/lib/python2.7/argparse.py", line 1688, in parse_args
        args, argv = self.parse_known_args(args, namespace)
      File "/usr/lib/python2.7/argparse.py", line 1720, in parse_known_args
        namespace, args = self._parse_known_args(args, namespace)
      File "/usr/lib/python2.7/argparse.py", line 1929, in _parse_known_args
        stop_index = consume_positionals(start_index)
      File "/usr/lib/python2.7/argparse.py", line 1885, in consume_positionals
        take_action(action, args)
      File "/usr/lib/python2.7/argparse.py", line 1794, in take_action
        action(self, namespace, argument_values, option_string)
      File "/usr/lib/python2.7/argparse.py", line 1090, in __call__
        namespace, arg_strings = parser.parse_known_args(arg_strings, namespace)
      File "/usr/lib/python2.7/argparse.py", line 1706, in parse_known_args
        if not hasattr(namespace, action.dest):
    TypeError: hasattr(): attribute name must be string

def start():

    parser = create_args()
    args = vars(parser.parse_args())



if __name__ == "__main__":
    start()

Answer 1

您可能想看看这个：

choices = {..
        "producer" : (
            ('-p', '--producer'),
            {'required':True, 'help': "Producer\'s(source account)"}
        ),
        "consumer" : (
            ('-c', '--consumer'),
            {'required':True, 'help': "Consumer\'s(destination account)"}
        ),
        "uuid" : (
            ('-u', '--uuid'),
            {'required':True, 'help': "file ID number"}
        )
}
for arg in args:
    options.add_argument(*choices[arg][0], **choices[arg][1])

add_argument的方法签名如下所示：

add_argument(name or flags...[, action][, nargs][, const][, default][, type][, choices][, required][, help][, metavar][, dest])

名称或标记部分作为*args收到，因此其他所有内容都必须命名。您通过使用**kwargs扩展字典来传递命名args。在你的情况下，你传递一个元组，它试图使用它（因为它是一个单一的参数）作为name or flag并且错误。

Python Argparse重用属性TypeError：hasattr（）：属性名必须是字符串

1 个答案: