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Question

我使用bodyWithPolygonFromPath来定义物理体的体积，并使用

获取所需的路径。但这条路似乎不正确，我希望看到物理体路径的边界线，看看形状是否正确。

有没有办法看到物理学家的音量大纲？

我尝试了以下代码，但它不起作用。

ship = [SKSpriteNode spriteNodeWithImageNamed：@“Spaceship”];

CGFloat offsetX = ship.frame.size.width * ship.anchorPoint.x;
CGFloat offsetY = ship.frame.size.height * ship.anchorPoint.y;

CGMutablePathRef path = CGPathCreateMutable();

CGPathMoveToPoint(path, NULL, 50 - offsetX, 110 - offsetY);
CGPathAddLineToPoint(path, NULL, 18 - offsetX, 16 - offsetY);
CGPathAddLineToPoint(path, NULL, 140 - offsetX, 15 - offsetY);

CGPathCloseSubpath(path);

SKShapeNode *yourline = [SKShapeNode node];
yourline.name = @"yourline";
yourline.path = path;
[yourline setStrokeColor:[UIColor redColor]];
 [self addChild:yourline];


ship.physicsBody = [SKPhysicsBody bodyWithPolygonFromPath:path];
//[ship setScale:0.5];
ship.zRotation = - M_PI / 2;

Answer 1

对于Objective-C＆amp; iOS＆lt; 7.1

在 ViewController.m 中找到此代码

SKView *skView = (SKView *)self.view;
skView.showsFPS = YES;
skView.showsNodeCount = YES;

在最后一行添加

之后

skView.showsPhysics = YES;

构建并运行，您应该看到所有物理主体边界线

我注意到你将shapeNode添加到self而不是spriteNode，所以请尝试以下

SKSpriteNode *ship = [SKSpriteNode spriteNodeWithImageNamed:@"Spaceship"];
CGFloat offsetX = ship.frame.size.width * ship.anchorPoint.x;
CGFloat offsetY = ship.frame.size.height * ship.anchorPoint.y;

CGMutablePathRef path = CGPathCreateMutable();
CGPathMoveToPoint(path, NULL, 50 - offsetX, 110 - offsetY);
CGPathAddLineToPoint(path, NULL, 18 - offsetX, 16 - offsetY);
CGPathAddLineToPoint(path, NULL, 140 - offsetX, 15 - offsetY);
CGPathCloseSubpath(path);

ship.physicsBody = [SKPhysicsBody bodyWithPolygonFromPath:path];

[self addChild:ship];

SKShapeNode *shape = [SKShapeNode node];
shape.path = path;
shape.strokeColor = [SKColor colorWithRed:1.0 green:0 blue:0 alpha:0.5];
shape.lineWidth = 1.0;
[ship addChild:shape];

对于Swift＆amp; iOS＆gt; = 8.0

let skView = self.view as! SKView
skView.showsFPS = true
skView.showsNodeCount = true
skView.showsPhysics = true

如果您想要自定义边线

let ship = SKSpriteNode(imageNamed: "Spaceship")
let offsetX = ship.frame.size.width * ship.anchorPoint.x
let offsetY = ship.frame.size.height * ship.anchorPoint.y

let path = CGPathCreateMutable()
CGPathMoveToPoint(path, nil, 50 - offsetX, 110 - offsetY)
CGPathAddLineToPoint(path, nil, 18 - offsetX, 16 - offsetY)
CGPathAddLineToPoint(path, nil, 140 - offsetX, 15 - offsetY)
CGPathCloseSubpath(path)

ship.physicsBody = SKPhysicsBody(polygonFromPath: path)
addChild(ship)

let shape = SKShapeNode()
shape.path = path
shape.strokeColor = SKColor(red: 1.0, green: 0, blue: 0, alpha: 0.5)
shape.lineWidth = 1.0
addChild(shape)

已经测试过：]

祝你好运!!

Answer 2

出于测试目的，我将船舶设置为SKShapeNode，暂时注释掉你的SKShapeNode，并将ship.path设置为与SKPhysicsBody相同的路径。

或者你可以使用它：

https://github.com/ymc-thzi/physicsDebugger

Answer 3

在新的7.1测试版中，有如上所述的功能。

Answer 4

我知道这有点晚了，但我想你可能会对我的新工具感兴趣，它会自动在精灵图像周围创建一条路径（所以你不必自己手动点击这些点），然后你可以调整各种设置，以更好地满足您的要求。该工具还输出Objective C和Swift程序代码，用于添加精灵物理主体的路径。希望它对某些人有帮助。感谢：

http://www.radicalphase.com/pathgen/

Answer 5

您的形状节点代码是正确的。看起来yourline可能会在实际船只之前添加到场景中，因此船舶精灵将被绘制在它之上，使其变得模糊。确保将yourline.zPosition设置为最高值，或确保在[self addChild:yourline]之后执行[self addChild:ship]。

Answer 6

这将在节点顶部添加红线形状。使用与为节点的物理主体定义的路径相同的路径。

+(void)debugPath:(CGPathRef)path onNode:(SKNode*)node {
    SKShapeNode *yourline = [SKShapeNode node];
    yourline.name = @"yourline";
    yourline.path = path;
    [yourline setStrokeColor:[UIColor redColor]];
    [node addChild:yourline];
}

即。用法：

[[self class] debugPath:ship.physicsBody.path onNode:ship];

Answer 7

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在GameViewController.swift

添加此行

override func viewDidLoad() {
    ...        
    if let view = self.view as! SKView? {
        ...
    }
    view.showsPhysics = true // <--- add this line
}

有没有办法直观地看到精灵套件的SKPhysicsbody边界线？

7 个答案:

对于Objective-C＆amp; iOS＆lt; 7.1

对于Swift＆amp; iOS＆gt; = 8.0

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