我有一个递归查询,封装在一个函数中,返回一个层次调查“结构”:
CREATE OR REPLACE FUNCTION get_survey_results(IN v_survey_id integer DEFAULT 1, IN v_survey_session_id integer DEFAULT NULL)
RETURNS TABLE(sort_order bigint[], survey_question_id integer, question_text text, required_ind smallint, survey_session_id integer, custom_text text, option_value integer, survey_scale_id integer, survey_scale_type_id integer, parent_survey_question_id integer, parent_survey_scale_option_id integer) AS
$BODY$
BEGIN
RETURN QUERY
WITH RECURSIVE Survey_Structure (PATH, survey_question_id, question_text,
required_ind, survey_session_id, custom_text,
option_value, survey_scale_id, survey_scale_type_id,
parent_survey_question_id, parent_survey_scale_option_id, CYCLE)
AS (
SELECT ARRAY[row_number() OVER (ORDER BY Survey_Question.sort_order)], Survey_Question.survey_question_id, Survey_Question.question_text,
Survey_Question.required_ind, Survey_Response.survey_session_id, Survey_Response.custom_text,
Survey_Scale_Option.option_value, Survey_Question.survey_scale_id, Survey_Scale.survey_scale_type_id,
0 as parent_survey_question_id, 0 AS parent_survey_scale_option_id, FALSE
FROM ...etc...
我可以将survey_id传递给此函数(SELECT * FROM get_survey_results(1)
),并返回该调查的所有问题和答案。
我想通过使用以下方法确定层次结构中节点的“级别”:
SELECT question_text, array_length(sort_order) AS level,
...etc...
FROM get_survey_results(1)
我的查询返回错误
函数array_length(bigint [])不存在
PostgreSQL array documentation承诺arrar_length()将处理“anyarray”。
我做错了什么?我需要安装一个可选包吗?
答案 0 :(得分:22)
对文档的仔细检查表明,array_length()
需要两个参数。
我只需要改变
SELECT question_text, array_length(sort_order) AS level, ...
到
SELECT question_text, array_length(sort_order, 1) AS level, ...