Question

我的查询是这样的。我试图获得一个id列表的状态。

select order_number, order_status_name
from data.order_fact s
join data.order_status_dim l
on s.order_status_key = l.order_status_key
where 
order_number in (1512011196169,1512011760019,1512011898493,1512011972111)

我收到一个错误，但是说：

ERROR:  operator does not exist: character varying = bigint
LINE 6: order_number in (1512011196169,1512011760019,1512011898493,1...
                     ^
HINT:  No operator matches the given name and argument type(s). You might need to add explicit type casts.

你是否有任何关于我应该如何改革ids以使其发挥作用的线索？非常感谢！

Answer 1

您的order_number是varchar，您无法将其与数字进行比较（123是SQL中的数字，'123'是字符串常量）

您需要使用字符串文字：

order_number in ('1512011196169','1512011760019','1512011898493','1512011972111')

手册中的更多细节：
http://www.postgresql.org/docs/current/static/sql-syntax-lexical.html#SQL-SYNTAX-CONSTANTS

Answer 2

如果您无法更改in中的数字类型，则可以使用cast：

select * from numbers_as_string
where cast(my_numbers_as_string as int) in (1,2,3)

Postgres：错误：运算符不存在：字符变化= bigint

2 个答案: