Question

我正在编写一个以10个浮点数作为输入的程序。但是，每当我输入小数时，程序都会向我发送错误。我的问题是：如何编辑我当前的try-catch异常以仅捕获字母等，并允许输入小数（然后将它们存储到数组中）。此外，无论这个问题如何，我的程序也会多次输出平均值，并且总是说它等于0.

以下是该计划：

import java.util.Scanner;

公共班平均{

public static void main(String[] args) {

    new Average().average(new double[10]);
}

public double average(double[] number) {
    Scanner scanner = new Scanner(System.in);

    int x = 0;
    double sum = 0;
    double[] numberList = new double[10]; //array to hold all numbers
    double[] largerList = new double[10]; //array to hold numbers greater than the average


    int numberIndex = 0;
    int largerIndex = 0;



    System.out.printf("Please enter 10 floating-point numberes.\nIf more than 10 values are entered, the numbers following 10 are ignored.\nIf less than 10 numbers are entered, the program will wait for you to enter 10.\n");

    for (int i = 0; i < 10; i++) {


        try { //try catch exception to catch decimal inputs as well as more /less than 10 integers
            x = scanner.nextInt();
            sum += numberList[x]; //add up all inputs to find sum
        } catch (Exception e) {
            System.out.println("Invalid input! Please reenter 10 integer values.");
            scanner = new Scanner(System.in);
            i = -1;
            numberIndex = 0;
            largerIndex = 0;
            numberList = new double[10];
            largerList = new double[10];
            continue;
        }
    }

    for (int i = 0; i < number.length; i++) {
        sum = sum + number[i];
        double average = sum / number.length;

        //return average;

        if (x > average) {
            largerList[largerIndex] = x; //add negative input to negativeList array
            largerIndex = largerIndex + 1;

        }
        System.out.println("Average value of your input is: " + average);
        System.out.println();

    }



    for (int i = 0; i < largerIndex; i++) {
        System.out.println(largerList[i]);
    }
    return 0;





}

}

Answer 1

您正在使用nextInt（）函数，该函数仅返回整数。 Int不能包含小数。请参考API并查看nextFloat（）和nextDouble（）方法。

Answer 2

对于您的平均问题，您的print语句将进入for循环，因此它将执行number.length次。将print语句移到循环外部。您还需要将平均变量的声明放在循环之外。你也应该只需要循环来计算总和，你不需要每次计算平均值

double average;
for(/*loop conditions*/)
{
    sum = sum + number[i];
}
average = sum / number.length;
System.out.println("Average value of your input is: " + average);
System.out.println();

编辑异常e以捕获字母而非小数

2 个答案: