Question

我需要查找截图的子页面数量。，
鉴于：， 1）页面总高度，
2）1个子页面的高度，
3）每个连续的屏幕截图高度与上面的屏幕重叠＆＃34; 5＆＃34;像素

Ex : Page height = 100 px
     1 Screen height (subpage) = 20px
     Then,
     1st screenshot : 0px to 20 px
     2nd screenshot : 15px to 35px.. and so on

由于

Answer 1

private int GetSubPageCount(int heightOfPage)
{
    int heightOfSubPage = 20;
    int overlap = 5;
    // that gives you count of completely filled sub pages
    int subPageCount = (heightOfPage - overlap) / (heightOfSubPage - overlap);

    // if last sub page is not completely filled, than add one page
    if ((heightOfPage - overlap) % (heightOfSubPage - overlap) > 0)
        subPageCount++;

    return subPageCount;
}

或者您可以使用舍入到最大整数值的浮点数，该整数值大于或等于完全填充的子页数：

private int GetSubPageCount(int heightOfPage)
{
    int heightOfSubPage = 20;
    int overlap = 5;
    return (int)Math.Ceiling((double)(heightOfPage - overlap) / (heightOfSubPage - overlap));
}

Answer 2

您可以使用简单的公式：

  number = (page_height - overlap) / (subpage_height - overlap)

如果数字是小数一个（例如5.123），你应该将其整理（5.123到6）。

例如，如果page_height = 100，subpage_height = 20且overlap = 5，我们可以推导出

number = (100 - 5) / (20 - 5) = 6.333333 
number = 7 (rounded up)

示例代码：

public static int SubPageCount(int pageHeight, int height, int overlap) {
  int result = (pageHeight - overlap) / (height - overlap);

  // If there's a fractional part - i.e. remainder in not 0
  // one should round the result up: add 1 
  if (((pageHeight - overlap) % (height - overlap)) != 0)
    result += 1;

  return result;
}

重叠距离的页数逻辑

2 个答案: