目前我可以使用vba将文本文件导入excel。但是,我无法弄清楚如何将文本文件中的数据复制到当前工作簿中。每次运行程序时,它都会为每个文本文件打开一个新的工作簿。
Sub CopyData()
Dim fileDialog As fileDialog
Dim strPathFile As String
Dim strFileName As String
Dim strPath As String
Dim dialogTitle As String
Dim wbSource As Workbook
Dim rngToCopy As Range
Dim rngRow As Range
Dim rngDestin As Range
Dim lngRowsCopied As Long
dialogTitle = "Navigate to and select required file."
Set fileDialog = Application.fileDialog(msoFileDialogFilePicker)
With fileDialog
.InitialFileName = "C:\Users\User\Documents"
.AllowMultiSelect = True
.Filters.Clear
.Title = dialogTitle
If .Show = False Then
MsgBox "File not selected to import. Process Terminated"
Exit Sub
End If
strPathFile = .SelectedItems(1)
End With
Workbooks.OpenText Filename:=strPathFile, _
Origin:=xlWindows, StartRow:=1, DataType:=xlDelimited, TextQualifier:= _
xlDoubleQuote, ConsecutiveDelimiter:=False, Tab:=True, Semicolon:=False, _
Comma:=False, Space:=False, Other:=False, FieldInfo:=Array(1, 1), _
TrailingMinusNumbers:=True
Set fileDialog = Nothing
Set rngRow = Nothing
Set rngToCopy = Nothing
Set wbSource = Nothing
Set rngDestin = Nothing
MsgBox "The data is copied"
End Sub
答案 0 :(得分:0)
虽然Siddart为您提供了链接,但您也可以尝试下面的链接。 我刚刚添加了一些修复程序,以某种方式帮助您获得所需的内容。
<强> EDIT2:强>
Sub CopyData()
Dim fileDia As FileDialog
Dim i As Integer
Dim done As Boolean
Dim strpathfile As String, filename As String
'--> initialize variables here
i = 1
done = False
Set fileDia = Application.FileDialog(msoFileDialogFilePicker)
With fileDia
.InitialFileName = "C:\Users\" & Environ$("username") & "\Documents"
.AllowMultiSelect = True
.Filters.Clear
.title = "Navigate to and select required file."
If .Show = False Then
MsgBox "File not selected to import. Process Terminated"
Exit Sub
End If
'--> you need to iterate to the files selected, open and dump each in your current wb
Do While Not done
On Error Resume Next
strpathfile = .SelectedItems(i)
On Error GoTo 0
If strpathfile = "" Then
done = True
Else
filename = Mid(strpathfile, InStrRev(strpathfile, "\") + 1, Len(strpathfile) - (InStrRev(strpathfile, "\") + 4))
'--> I added this because the maximum lengh of sheet name is 31.
'--> It will throw error if you exceed 31 characters.
If Len(filename) > 31 Then filename = Left(filename, 26)
'--> use the transfer sub here, take note of the new ByVal argument
Transfer strpathfile, filename
'Debug.Print filename
strpathfile = ""
i = i + 1
End If
Loop
End With
Set fileDia = Nothing
End Sub
支持子(Edit2):
Sub Transfer(mySource As String, wsName As String)
Dim wbSource As Workbook
Dim wsDestin As Worksheet
Dim lrow As Long
Set wsDestin = ThisWorkbook.Sheets.Add(, ThisWorkbook.Sheets(ThisWorkbook.Sheets.Count)) 'Add the worksheet at the end
On Error Resume Next
wsDestin.Name = wsName 'set the name
On Error GoTo 0
Application.DisplayAlerts = False
If InStr(wsDestin.Name, "Sheet") <> 0 Then wsDestin.Delete: Exit Sub
Workbooks.OpenText filename:=mySource, _
Origin:=xlWindows, StartRow:=1, DataType:=xlDelimited, TextQualifier:= _
xlDoubleQuote, ConsecutiveDelimiter:=False, Tab:=True, Semicolon:=False, _
Comma:=False, Space:=False, Other:=False, FieldInfo:=Array(1, 1), _
TrailingMinusNumbers:=True
Set wbSource = ActiveWorkbook
With wsDestin
'--> get the last row of your destination sheet, i assumed you want Column A
lrow = .Range("A" & Rows.Count).End(xlUp).Row
'--> not comfortable in UsedRange but this should work, else define your range.
'--> i can't because, i can't see your actual data
wbSource.Sheets(1).UsedRange.Copy .Range("A" & lrow).Offset(1, 0)
wbSource.Close False
End With
Application.DisplayAlerts = True
End Sub
希望这与您的需求有些接近 已经过测试,工作正常 但我不确定您是否同意我如何为您的工作表名称添加唯一标识符 我选择了床单当前计数 将该部分更改为您想要的任何内容 现在,如果文件已经加载,则忽略该文件。