Question

我有一个高容量的java应用程序，我必须将http帖子发送到另一台服务器。目前我正在使用 org.apache.commons.httpclient 库：

private static void sendData(String data) {
HttpClient httpclient = new HttpClient();
StringRequestEntity requestEntity;
try {
    requestEntity = new StringRequestEntity(data, "application/json", "UTF-8");
    String address = "http://<my host>/events/"
    PostMethod postMethod = new PostMethod(address);
    postMethod.setRequestEntity(requestEntity);

    httpclient.executeMethod(postMethod);

} catch (Exception e) {
    LOG.error("Failed to send data ", e);

}
}

这意味着我正在同步发送我的http请求，这不适合我的多线程高容量应用。所以我想将这些调用更改为异步非阻塞http调用。

我经历了apache async client和xsocket等众多选项，但无法使其发挥作用。

尝试ning：

private static void sendEventToGrpahiteAsync(String event) {
LOG.info("\n" + "sendEventToGrpahiteAsync");
try (AsyncHttpClient asyncHttpClient = new AsyncHttpClient()) {
    BoundRequestBuilder post = asyncHttpClient.preparePost();
    post.addHeader("Content-Type", "application/json");
    post.setBodyEncoding("UTF-8");
    post.setBody(event);
    post.execute(new HttpRequestCompletionHandler());
} catch (Exception e) {
    LOG.error("Failed to sending event", e);
}
}

我尝试了Apache HttpAsyncClient：

private static void sendEventToGrpahiteAsync(String event) {
LOG.info("\n" + "sendEventToGrpahiteAsync");
try (CloseableHttpAsyncClient httpclient = HttpAsyncClients.createDefault()) {
    httpclient.start();
    HttpPost request = new HttpPost(addr);
    StringEntity entity = new StringEntity(event, ContentType.create("application/json", Consts.UTF_8));
    request.setEntity(entity);
    httpclient.execute(request, null);
} catch (Exception e) {
    LOG.error("Failed to sending event", e);
}
}

我尝试了xsocket：

private static void sendEventToGrpahiteAsync2(String event) {
LOG.info("\n" + "sendEventToGrpahiteAsync");
try (INonBlockingConnection con = new NonBlockingConnection(<SERVER_IP>, 80);
    IHttpClientEndpoint httpClientConnection = new HttpClientConnection(con)) {
    IHttpResponseHandler responseHandler = new MyResponseHandler();
    IHttpRequest request = new PostRequest(url_address, "application/json", Consts.UTF_8.toString(), event);
    request.setTransferEncoding(Consts.UTF_8.toString());
    httpClientConnection.send(request, responseHandler);
} catch (Exception e) {
    LOG.error("Failed to sending event", e);
}
}

我没有例外但是帖子也没有到达目标。要清楚，目标是graphite server，所以一旦帖子到达，就会在图表中清楚地看到。同步帖很好用，我可以在图表上看到结果，但我的目标图上没有显示任何异步帖子。

我错过了什么？

由于

Answer 1

知道了。

我使用的所有库都是使用额外的IO线程实现的，所以我的进程可能在完全握手之前结束。

一旦我在http调用之后添加了Thread.sleep（2000）就行了。所以对于一个Web应用程序（这是我的情况）我建议的实现很好（但对于java进程，你可能会考虑NickJ的答案）。

Answer 2

您可以使用Java Executor框架：

首先，创建一个Callable来完成你的工作：

public class MyCallable implements Callable<MyResult> {
  @Override
  public MyResult call() throws Exception {
    //do stuff
    return result;
  }
}

获取将运行Callable的Exectutor。有一种方法可以得到一个，这是一个例子：

ExecutorService executor = Executors.newFixedThreadPool(NTHREDS);

最后，运行它：

MyCallable callable = new MyCallable();
Future<MyResult> futureResult = executor.submit(callable);

获得结果：

boolean resultReady = futureResult.isDone(); //is the result ready yet?
Result r = futureResult.get(); //wait for result and return it

try {
  Result r = futureResult.get(10, TimeUnit.SECONDS); //wait max. 10 seconds for result
} catch (TimeOutException e) {
  //result still not ready after waiting 10 seconds
}

java非阻塞HTTP客户端

2 个答案: