Question

当我运行以下查询时，我收到一个错误，指出错误的参数数量：

SELECT
population_postcodes.*, 
target_postcodes.*, 
SQR( EXP(population_postcodes.longitude- target_postcodes.longitude, 2) + EXP(population_postcodes.latitude-target_postcodes.latitude, 2) ) as distance
FROM population_postcodes INNER JOIN target_postcodes on Population_postcodes.Population_postcode = Target_postcodes.Target_postcode;

有人可以建议我如何解决这个问题吗？

我也尝试过以下代码：

SELECT Population_postcodes.*, Target_postcodes.* 

FROM population_postcodes
INNER JOIN target_postcodes
ON Population_postcodes.Population_postcode = Target_postcodes.Target_postcode
SQR( (population_postcodes.longitude- target_postcodes.longitude)^2 + (population_postcodes.latitude-target_postcodes.latitude)^2 ) as distance;

这段代码：

     SELECT Population_postcodes.*, Target_postcodes.*, SQR( (population_postcodes.longitude- target_postcodes.longitude)^2 + (population_postcodes.latitude-target_postcodes.latitude)^2 ) as distance
FROM population_postcodes
INNER JOIN target_postcodes
ON Population_postcodes.Population_postcode = Target_postcodes.Target_postcode;

Answer 1

Exp需要一个参数，你给两个。

旧：EXP(population_postcodes.longitude- target_postcodes.longitude, 2)

新：(population_postcodes.longitude- target_postcodes.longitude)*(population_postcodes.longitude- target_postcodes.longitude)

Answer 2

尝试替换......

EXP(<expression>, 2)

...到...

<expression>^2

在Access中，EXP函数返回e（自然对数的基数）上升到幂。要将表达式提升为幂，请使用^运算符。

在您的情况下，请小心将括号括在表达式周围，例如......

(population_postcodes.longitude- target_postcodes.longitude)^2

...强制最后施加电源。默认情况下，^运算符在 - 运算符之前计算。

参数数量错误SQL MS ACCESS

2 个答案: