Question

如果执行异常，有没有办法阻止try块的其余部分执行？比方说，我已经用完了ingredient 1，如果执行该异常，如何防止执行块的其余部分执行？

try:
    #add ingredient 1
    #add ingredient 2
    #add ingredient 3
except MissingIngredient:
    print 'you are missing ingredients'

Answer 1

它会自动发生：

class MissingIngredient(Exception):
    pass

def add_ingredient(name):
    print 'add_ingredient',name
    raise MissingIngredient

try:
    add_ingredient(1)
    add_ingredient(2)
    add_ingredient(3)
except MissingIngredient:
    print 'you are missing ingredients'

如果其中一个表达式引发异常，则不会执行其余的try块。它会打印出来：

add_ingredient 1
you are missing ingredients

Answer 2

在原始try块中使用另一个try / catch块。

try:
    #add ingredient 1
    #add ingredient 2
    #add ingredient 3
except MissingIngredient:
    try:
         ....
    except MissingIngredient:
         ....

    print 'you are missing ingredients'

但是，可能以下结构更好：

try:
    #add ingredient 1

    try:
        #add ingredient 2

        try:
            #add ingredient 3

            # Here you can assume ingredients 1, 2 and 3 are available.

        except MissingIngredient:
            # Here you know ingredient 3 is missing

    except MissingIngredient:
        # Here you know ingredient 2 is missing

except MissingIngredient:
    # Here you know ingredient 1 is missing

Answer 3

没有。它应该立即从try块中拉出到except子句;我知道继续前进的唯一方法是尝试......除了......最后......

如果执行异常，有没有办法阻止执行try块？

3 个答案: