使用一个MySQL语句计算所有案例

Question

我想返回总计数，然后还返回where语句的结果。

SELECT count(cases) 
from `table`
WHERE stats = 'open'.

以上将计算stats = open的位置，我需要首先计算所有情况，然后还要计算where语句。类似的东西：

SELECT count(cases)
from `table`
\\return count of all cases
where stats= count(open).

Answer 1

SELECT SUM( stats = 'open' ),  -- count of all stats open
       SUM( stats <> 'open' )  -- count of all stats NOT open
from `table`;

Answer 2

尝试使用：

SELECT COUNT(cases)
FROM `table`
HAVING stats = COUNT(open)