我的搜索是使用listView完成的,所以当用户键在firstname的第一个字母时,它会返回结果,如何让它在Android中显示“找不到结果”? 请指教,我是否需要创建一个TextView?
public class ListViewAdapter extends BaseAdapter {
// Declare Variables
Context mContext;
LayoutInflater inflater;
private List<User> namelist = null;
private ArrayList<User> arraylist;
public ListViewAdapter(Context context,
List<User> worldpopulationlist) {
mContext = context;
this.namelist = worldpopulationlist;
inflater = LayoutInflater.from(mContext);
this.arraylist = new ArrayList<User>();
this.arraylist.addAll(namelist);
}
public class ViewHolder {
TextView firstname;
TextView lastname;
TextView position;
TextView company;
ImageView pix;
TextView searchresult;
}
@Override
public int getCount() {
return namelist.size();
}
@Override
public User getItem(int position) {
return namelist.get(position);
}
@Override
public long getItemId(int position) {
return position;
}
public View getView(final int position, View view, ViewGroup parent) {
final ViewHolder holder;
if (view == null) {
holder = new ViewHolder();
view = inflater.inflate(R.layout.listview_item, null);
// Locate the TextViews in listview_item.xml
holder.firstname = (TextView) view.findViewById(R.id.firstname);
holder.lastname = (TextView) view.findViewById(R.id.lastname);
holder.position= (TextView) view.findViewById(R.id.position);
holder.company = (TextView) view.findViewById(R.id.company);
// Locate the ImageView in listview_item.xml
holder.pix = (ImageView) view.findViewById(R.id.pix);
view.setTag(holder);
} else {
holder = (ViewHolder) view.getTag();
}
// Set the results into TextViews
holder.firstname.setText(namelist.get(position).getFirstName());
holder.lastname.setText(namelist.get(position).getLastName());
holder.position.setText(namelist.get(position).getDesignation());
holder.company.setText(namelist.get(position).getCompanyName());
// Set the results into ImageView
holder.pix.setImageResource(namelist.get(position).getProfileImage());
// Listen for ListView Item Click
view.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View arg0) {
// Send single item click data to SingleItemView Class
Intent intent = new Intent(mContext, SingleItemView.class);
// Pass all data country
intent.putExtra("firstname",
(namelist.get(position).getFirstName()));
intent.putExtra("lastname",
(namelist.get(position).getLastName()));
// Pass all data rank
intent.putExtra("position",
(namelist.get(position).getDesignation()));
// Pass all data population
intent.putExtra("company",
(namelist.get(position).getCompanyName()));
// Pass all data flag
intent.putExtra("pix",
(namelist.get(position).getProfileImage()));
// Start SingleItemView Class
mContext.startActivity(intent);
}
});
return view;
}
// Filter Class
public void filter(String charText) {
charText = charText.toLowerCase(Locale.getDefault());
namelist.clear();
if (charText.length() == 0) {
namelist.addAll(arraylist);
} else {
for (User wp : arraylist) {
if (wp.getFirstName().toLowerCase(Locale.getDefault()).contains(charText)||wp.getLastName().toLowerCase(Locale.getDefault()).contains(charText) ) {
namelist.add(wp);
}
else
{
//what should I enter here?
}
}
}
notifyDataSetChanged();
}
}
答案 0 :(得分:0)
您可以创建Toast,而不是创建TextView,它实际上是一个弹出窗口。您可以像这样创建它:
Toast.makeText(mContext, "No Results Found", Toast.LENGTH_SHORT).show();
如果您希望弹出窗口持续更长时间,可以将最后一个参数更改为Toast.LENGTH_LONG。
答案 1 :(得分:0)
在我的应用程序中,对于这种情况,我在列表中有一个具有特殊类型'EMPTY_RESULT'的项目。
基本上,在输出EMPTY结果后,生成一个特定类型为'EMPTY_RESUT'的适配器项(表示getCount()== 1),并通知数据集更改。
然后,当调用getView时,返回空项,当然你可以为它设计一些UI来呈现空结果,例如图标和文本“找不到任何东西”。