我有两张桌子:
person
id
name
car
name
person_id
目前查询如下:
SELECT
person.name
car.name
FROM
person, car
WHERE
person.id = car.person_id
现在,如果有人与某人相关联,这项工作正常。但是,如果没有,那么这个人就不会被退回。如果一个人没有车,我想在第'No Car'
栏中返回包含car.name
文字的行。
答案 0 :(得分:3)
select person.name, coalesce(car.name, 'no car')
from person
left outer join car on person.id = car.person_id
答案 1 :(得分:0)
SELECT person.name, CASE WHEN car.name IS NULL THEN 'no car' ELSE car.name END
FROM person
LEFT JOIN car ON person.id = car.person_id
答案 2 :(得分:-1)
select person.name, ISNULL(car.name, 'no car')
from person
left join car on person.id = car.person_id