Question

我在网上发现了很多方法，但是他们没有帮助我，我的问题是如何在不获取重复条目的情况下将项目添加到列表视图我的PHP代码是

$result1 = mysql_query("select * from headlines where categoryID = '$category' and newID = '$hashtagID' order by id DESC", $db->connect());
  $count = mysql_num_rows($result1);
  if($count != 0){
      $response["success"] = 1;

      while($row1 = mysql_fetch_assoc($result1)){
          //getting user
          $result2 = mysql_query("select * from members where id = '".$row1['memberID']."'", $db->connect());
          while($row2 = mysql_fetch_assoc($result2)){
          $commentAuthor = $row2['last_name'];
          }

          $response['trends'][] = array('body'=>$row1['body'], 'name'=>$commentAuthor);

          }
      echo json_encode($response);


      }else{
          $response["success"] = 0;
          $response['trends'][] = array('body'=>'0', 'name'=>'0');
          echo json_encode($response);
          }
 }

以及下面的java代码使用异步任务执行该背景

UserFunctions userfunction = new UserFunctions();
        JSONObject json = userfunction.loadhash(currenthash,
                categoryID);

        try {
            if (json.get(KEY_SUCCESS) != null) {
                String rs = json.getString(KEY_SUCCESS);
                if (Integer.parseInt(rs) == 1) {
                    istweetempty = true;
                    JSONArray arrayjson = json.getJSONArray("trends");
                    for (int i = 0; i < arrayjson.length(); i++) {
                        JSONObject newobject = arrayjson.getJSONObject(i);
                        tweepList.add(0, newobject.getString("name")
                                .toString());
                        tweetList.add(0, newobject.getString("body")
                                .toString());
                    }

                } else {

                }
            }
        } catch (NumberFormatException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        } catch (JSONException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

我的问题就在这里，如果我将list_trending.setAdapter(tweets_adapter);与tweets_adapter.notifyDataSetChanged();一起使用，我的列表视图中会出现重复的条目，如果我使用tweets_adapter.notifyDataSetChanged();，则listview中的任何内容都不会发生服务器不会出现。我哪里可能出错。

@Override
    protected void onPostExecute(String[] result) {

        if (istweetempty == true) {
            tweepArray = tweepList.toArray(new String[tweepList.size()]);
            tweetArray = tweetList.toArray(new String[tweetList.size()]);
            tweets_adapter = new tweets(Trending.this, tweepArray,
                    tweetArray);
            //list_trending.setAdapter(tweets_adapter);
            tweets_adapter.notifyDataSetChanged();
        }
        list_trending.onRefreshComplete();

        super.onPostExecute(result);
    }

Answer 1

tweets_adapter.notifyDataSetChanged();

如何更新自定义列表视图

1 个答案: