我在XChat上看了另一个post,但它没有解决我的问题。
我想在freenode上使用Xchat:
/msg NickServ IDENTIFY <password>
You have not registered
Closing Link: 999.999.999.999 (Connection timed out)
#22*# Disconnected (Remote host closed socket).
Cycling to next server in Ubuntu Servers...
#22*# Disconnected ().
然后我按命令检查了我的昵称:
/whois <mynickname>
* Disconnected ().
* Looking up irc.freenode.net
* Connecting to chat.freenode.net (99.999.99.999) port 8001...
* Connected. Now logging in...
* *** Looking up your hostname...
* *** Checking Ident
* *** Couldn't look up your hostname
* *** No Ident response
* <mynickname> already in use. Retrying with <mynickname>..
然后我输入命令来请求我的密码,但在我的邮箱中没有收到任何消息:
/msg NickServ SENDPASS <mynickname>
#22*# *** Looking up your hostname...
#22*# *** Checking Ident
#22*# *** Couldn't look up your hostname
#22*# *** No Ident response
#22*# <mynickname> already in use. Retrying with <mynickname>...
#22*# <mynickname> already in use. Retrying with <mynickname>...
#22*# Nickname already in use. Use /NICK to try another.
Xchat Freenode一直在传递信息:
* *** Looking up your hostname...
* Disconnected (Connection reset by peer).
Cycling to next server in FreeNode...
* Disconnected ().
* Looking up irc.freenode.netnot woYou are not authorized to perform this operationrking
* Connecting to chat.freenode.net (999.999.999.999) port 8001...
* Connected. Now logging in...
* *** Looking up your hostname...
* *** Checking Ident
* *** Couldn't look up your hostname
有趣的是,每当我尝试通过link使用网络浏览器登录时,它就能很好地运行。甚至,如果我首先通过网络浏览器登录任何频道,然后我继续使用XChat并尝试在浏览器上首先登录其他频道,然后在XChat上工作没有问题。
现在,如果我尝试命令:
/whois <mynickname>
* [<mynickname>] (~<mynickname>@99.999.9.999): Linda Lowela
* [<mynickname>] #webkit
* [<mynickname>] dickson.freenode.net :US
* [<mynickname>] is connecting from *@99.999.9.999 99.999.9.999
* [<mynickname>] idle 00:00:51, signon: Wed Jan 1 21:12:31
* [<mynickname>] End of WHOIS list.
那么,这里发生了什么以及为什么XChat会出现这种奇怪的行为?
欢迎任何建议。
答案 0 :(得分:4)
当您打开XChat时,请尝试执行以下步骤:
从XChat提示符输入命令,在Freenode上选择它 - {nickname} | :{提示输入命令}
/ join#{channel-name}
它应该工作。此外,请查看此参考资料:The Book of IRC。