我正在尝试为我的对象实现IEqualityComparer,它基本上检测对象是否比另一个更旧。以下更简单的例子将综合我正在努力实现的目标:
class Program
{
static void Main(string[] args)
{
var authorsList = new List<Author>()
{
new Author{ Firstname = "Bob", Lastname = "Smith", Age=11 },
new Author{ Firstname = "Bob", Lastname = "Smith", Age=20 },
new Author{ Firstname = "Bob", Lastname = "Smith", Age=12 },
new Author{ Firstname = "Bob", Lastname = "Smith", Age=14 },
new Author{ Firstname = "Bob", Lastname = "Smith", Age=12 },
new Author{ Firstname = "Fred", Lastname = "Smith", Age=12 },
new Author{ Firstname = "Trevor", Lastname = "Smith", Age=15 },
new Author{ Firstname = "Brian", Lastname = "Smith", Age=11 },
new Author{ Firstname = "Billy", Lastname = "Smith", Age=11 },
};
var authorsListExcept = new List<Author>()
{
new Author{ Firstname = "Bob", Lastname = "Smith", Age=12 },
new Author{ Firstname = "Fred", Lastname = "Smith", Age=12 },
};
var authorsList2 = authorsList
.Except(authorsListExcept, new AuthorUpdatedComparer()).ToList();
}
}
class Author
{
public string Firstname { get; set; }
public string Lastname { get; set; }
public int Age { get; set; }
}
class AuthorUpdatedComparer : IEqualityComparer<Author>
{
public bool Equals(Author x, Author y)
{
return x.Age >= y.Age;
}
public int GetHashCode(Author obj)
{
//Check whether the object is null
if (Object.ReferenceEquals(obj, null)) return 0;
int FirstnameHash = (obj.Firstname ?? "").GetHashCode();
int LastnameHash = (obj.Lastname ?? "").GetHashCode();
int finalResult = FirstnameHash ^ LastnameHash;
return finalResult;
}
}
我的authorsList2结果将是: *鲍勃史密斯20岁 * Bom Smith,14岁 * Trevor Smith,15岁 * Brian Smith,11岁 *比利史密斯11岁
但不包括这个,不包括14岁的鲍勃史密斯。 在调试时,我得出的结论是,包括Bob Smith在20岁开始使用它之后的Comparer有一个比较器,在所有Bob小于20之后排除。
在我看来,这是一种奇怪的行为,它应该只排除那些年龄较小或年龄与authorsListExcept所包含的年龄相同的行为。 我试着阅读msdn文档,我想要它应该发生: 字体:http://msdn.microsoft.com/en-us/library/bb336390(v=vs.100).aspx
任何人都可以帮助我吗? 谢谢, 雨果萨尔加多
答案 0 :(得分:1)
以下LINQ查询提供了您期望的结果:
var result =
authorsList.GroupBy(x => Tuple.Create(x.Firstname, x.Lastname))
.SelectMany(g => g.Where(x => authorsListExcept.All(e => e.Firstname != x.Firstname || e.Lastname != x.Lastname || e.Age < x.Age)));
以下查询也会生成此结果。它应该表现得更好:
var result =
authorsList.GroupBy(x => Tuple.Create(x.Firstname, x.Lastname))
.GroupJoin(authorsListExcept, x => x.Key,
x => Tuple.Create(x.Firstname, x.Lastname),
(a, e) => a.Where(x => x.Age > e.Select(z => z.Age)
.DefaultIfEmpty(0)
.Max()))
.SelectMany(x => x)
第三个选项(与之前相同,但在查询语法中):
var result =
(from a in authorsList
group a by Tuple.Create(a.Firstname, a.Lastname) into g
join e in authorsListExcept on g.Key equals Tuple.Create(e.Firstname, e.Lastname) into er
from age in er.Select(x => x.Age).DefaultIfEmpty()
select g.Where(x => x.Age > age)).SelectMany(x => x);
接口IEqualityComparer<T>
用于检查相等。它与任何订购无关。因此,您不能以您尝试的方式使用它。
一般而言:此接口的实现应始终在GetHashCode
实现和Equals
方法中使用完全相同的属性集。
答案 1 :(得分:0)
如果我理解了你想要的东西,试试这个。
class Program
{
static void Main(string[] args)
{
var authorsList = new List<Author>()
{
new Author{ Firstname = "Bob", Lastname = "Smith", Age=11 },
new Author{ Firstname = "Bob", Lastname = "Smith", Age=20 },
new Author{ Firstname = "Bob", Lastname = "Smith", Age=12 },
new Author{ Firstname = "Bob", Lastname = "Smith", Age=14 },
new Author{ Firstname = "Bob", Lastname = "Smith", Age=12 },
new Author{ Firstname = "Fred", Lastname = "Smith", Age=12 },
new Author{ Firstname = "Trevor", Lastname = "Smith", Age=15 },
new Author{ Firstname = "Brian", Lastname = "Smith", Age=11 },
new Author{ Firstname = "Billy", Lastname = "Smith", Age=11 },
};
var authorsListExcept = new List<Author>()
{
new Author{ Firstname = "Bob", Lastname = "Smith", Age=12 },
new Author{ Firstname = "Fred", Lastname = "Smith", Age=12 },
};
var authorsList2 = authorsList.Where(x => !authorsListExcept.Any(y => y.Firstname == x.Firstname && y.Lastname == x.Lastname && x.Age <= y.Age));
}
}
public class Author
{
public string Firstname { get; set; }
public string Lastname { get; set; }
public int Age { get; set; }
}