Question

这里第一次是业余程序员，我有很多问题。我想做一个虚拟模型商店。我可以在向量中添加新项目，检查广告资源，但是当我想删除特定项目时（producer＆amp; name＆amp; scale），它会删除最后一项元件。

#include <iostream>
#include <string>
#include <fstream>
#include <vector>
using namespace std;

class model
{
private:
    int price;
    string scale, name, producer;
public:

    vector<model> vectorr;
    model();
    virtual ~model();
    int getprice();
    string getscale();
    string getname();
    string getproducer();

    void setprice(int);
    void setscale(string);
    void setname(string);
    void setproducer(string);
    friend ostream &operator>>(ostream &stream, model &mt);
    model &operator=(model &mt);
};

这就是标题。

#include <iostream>
#include "header1.h"
#include <string>
#include <conio.h>
#include <vector>
using namespace std;

int main()
{
    vector<machete> vectorr;
    machete c;
    machete t;

    cout << "Welcome to the shop , what do you want to do?" << endl;
    cout << "Chose your destiny : 1. Add  2.Get 3.Remove  4.Sort  0.Quit"   << endl;

    int menu, temp2;
    string temp;

    cin >> menu;

    while (menu != 0) {
        switch (menu) {
            case 0 : cout << "Bye bye";
                _getch();
                exit(1);
                break;
            case 1 : cout << "Enter a producer" << endl;
                cin >> temp;
                c.setproducer(temp);
                cout << "Enter a name" << endl;
                cin >> temp;
                c.setname(temp);
                cout << "Enter a scale" << endl;
                cin >> temp;
                c.setscale(temp);
                cout << "Enter a price" << endl;
                cin >> temp2;
                c.setprice(temp2);
                vectorr.push_back(c);
                cout << "You have succesfully added a model !" << endl;
                break;

            case 2 : cout << "Producer  |  Name  |  Scale  | Price" << endl;
                for (std::vector<model>::iterator it = vectorr.begin(); it != vectorr.end(); ++it) {
                    cout >> *it;
                }
                cout << endl;
                break;

            case 3 : cout << "What do you want to remove?" << endl;
                cout << "Enter the producer" << endl;
                string producer;
                cin >> producer;
                cout << "Enter the name" << endl;
                string name;
                cin >> name;
                cout << "Enter the scale" << endl;
                string scale;
                cin >> scale;
                for (unsigned i = 0; i < vectorr.size(); ++i) {
                    t.setname(vectorr[i].getnume());
                    t.setproducer(vectorr[i].getproducator());
                    t.setscale(vectorr[i].getscara());
                    if (t.getname() == name && t.getproducer() == producer && t.getscle() == scale) {
                        vectorr.erase(vectorr.begin() + i);
                        cout << "You have succesfully erased the " << name << " model" << endl;
                        break;
                    }
                }
                break;
        }
        cout << "Chose your destiny : 1. Add  2.Get  3.Remove  4.Sort  0.Quit" << endl;

        cin >> menu;
    }
    return 0;
}

这是主要的。 case 3是删除thingamajack的问题。它总是删除向量中的最后一个元素。 if（name = name等）工作正常，测试三次以确保不是问题。无论我写什么vectorr.erase，它都会按照我想要的方式运行。

对于凌乱的代码感到抱歉，我可能在case 3之前做错了什么，忽略case 4排序，还没有实现，感谢任何帮助，谢谢！

Answer 1

在案例2中，您已经写过

std::vector<model>::iterator it = vectorr.begin()

而你定义了

vector<machete> vectorr;

我认为你在大砍刀和模特之间感到困惑。

vector.erase - 它总是删除我的最后一个元素

1 个答案: