Question

我在尝试从字符串中获取HTTP响应的主体时遇到了困难。所以根据我的代码，我应该从名为“responseString”的字符串中的PHP页面得到响应，但是因为这是在ASynchTask中，我无法在其他任何地方访问该字符串，所以如何才能收到字符串？

例如，我想将此字符串拍摄到文本视图中以进行测试，我该怎么做？我是否错误地阅读了代码？我的反应是不是被放进那个字符串了？

这是我的代码：

class RequestTask extends AsyncTask<String, String, String>{

    @Override
    protected String doInBackground(String... uri) {
        HttpClient httpclient = new DefaultHttpClient();
        HttpResponse response;
        String responseString = null;
        try {
            response = httpclient.execute(new HttpGet(uri[0]));
            StatusLine statusLine = response.getStatusLine();
            if(statusLine.getStatusCode() == HttpStatus.SC_OK){
                ByteArrayOutputStream out = new ByteArrayOutputStream();
                response.getEntity().writeTo(out);
                out.close();
                responseString = out.toString();

            } else{
                //Closes the connection.
                response.getEntity().getContent().close();
                throw new IOException(statusLine.getReasonPhrase());
            }
        } catch (ClientProtocolException e) {
            //TODO Handle problems..
        } catch (IOException e) {
            //TODO Handle problems..
        }
        return responseString;
    }

    @Override
    protected void onPostExecute(String result) {
        super.onPostExecute(result);



    }
}

我正在使用以下命令执行：

new RequestTask().execute("http://www.mywebsite.com/android/registercheck.php?first=" + first2 + "&last=" + last2 + "&dispname=" + display2 + "&email=" + email2 + "&password=" + password2 );

Answer 1

执行doInBackground之后，onPostExecute将直接启动，并且您可以在那里更新UI，因为您要返回responseString，然后在onPostExecute中将其放入TextView

doInBackgound的回复是onPostExecute的忠诚，因此字符串result是您的responseString。

@Override
protected void onPostExecute(String result) {
    super.onPostExecute(result);

    tv.setText(result);

}

Answer 2

我认为你的问题还没有解决。所以，

对于Log或Toast使用以下代码：

class RequestTask extends AsyncTask<String, String, String>{
String responseString = "";
@Override
protected String doInBackground(String... uri) {
    HttpClient httpclient = new DefaultHttpClient();
    HttpResponse response;

    try {
        response = httpclient.execute(new HttpGet(uri[0]));
        StatusLine statusLine = response.getStatusLine();
        if(statusLine.getStatusCode() == HttpStatus.SC_OK){
            ByteArrayOutputStream out = new ByteArrayOutputStream();
            response.getEntity().writeTo(out);
            out.close();
            responseString = out.toString();

        } else{
            //Closes the connection.
            response.getEntity().getContent().close();
            throw new IOException(statusLine.getReasonPhrase());
        }
    } catch (ClientProtocolException e) {
        //TODO Handle problems..
    } catch (IOException e) {
        //TODO Handle problems..
    }
    return responseString;
}

@Override
protected void onPostExecute(String result) {
    super.onPostExecute(result);
    Log.d("Result is", responseString );
    Toast.makeText(YourClass.this , responseString , Toast.LENGTH_SHORT).show();
 }
}

如何使用AsyncTask读取HTTP响应？

2 个答案: