Question

我正在使用OAuth 2.0对我的用户进行身份验证，我必须发出http post请求（发送我的客户端ID，客户端密码等）。我想我是成功的。作为回应，我应该获取访问令牌和其他信息。但是当我在LogCat中打印响应时，它出现为“org.apache.http.message.BasicHttpResponse@407e7bb0”。我在哪里可以找到该消息？下面是我的代码，我按照这个示例http://www.androidhive.info/2011/10/android-making-http-requests/

public class PasteCode extends Activity {

@Override
protected void onCreate(Bundle savedInstanceState) {
    // TODO Auto-generated method stub
    super.onCreate(savedInstanceState);
    setContentView(R.layout.pastecode);

    final EditText codeinput = (EditText) findViewById(R.id.editText1);

    Button send_btn = (Button) findViewById(R.id.button1);
    send_btn.setOnClickListener(new View.OnClickListener() {

        @Override
        public void onClick(View v) {

            final String code = codeinput.getText().toString();

            new Thread( new Runnable() {
                @Override
                public void run() {

         HttpClient httpClient = new DefaultHttpClient();
     HttpPost httpPost = new HttpPost("https://accounts.google.com/o/oauth2/auth?");

     ArrayList<NameValuePair> nameValuePair = new ArrayList<NameValuePair>(5);
     nameValuePair.add(new BasicNameValuePair("code", code));
     nameValuePair.add(new BasicNameValuePair("client_id", "---------"));
     nameValuePair.add(new BasicNameValuePair("client_secret", "---"));
     nameValuePair.add(new BasicNameValuePair("redirect_uri", "urn:ietf:wg..."));
     nameValuePair.add(new BasicNameValuePair("grant_type", "authorization_code"));

try {
    httpPost.setEntity(new UrlEncodedFormEntity(nameValuePair));

    } catch (UnsupportedEncodingException e) {
    // writing error to Log
     e.printStackTrace();
    }

     // Making HTTP Request

try {
     HttpResponse response = httpClient.execute(httpPost);

     // writing response to log
     Log.d("Http Response:", response.toString());
    } catch (ClientProtocolException e) {
    // writing exception to log
     e.printStackTrace();
     } catch (IOException e) {
     // writing exception to log
     e.printStackTrace();

     }

     }
    }).start();

    }
});
}

}

Answer 1

您可以使用BufferedReader：

BufferedReader rd = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));
StringBuilder builder = new StringBuilder();
String str = "";

while ((str = rd.readLine()) != null) {
    builder.append(str);
}

String text = builder.toString();

Answer 2

nikis的答案应该可以正常工作，但我觉得这个static method found in EntityUtils要简洁一些。如果你看here，你会发现实现相对类似。

如何阅读Http响应

2 个答案: