Question

我正在制作Android应用（最小SDK：8，目标SDK：19）

现在我想在开始时设置一个加载图标，直到应用程序检查互联网中心性

直到现在我没有问题

我有这个方法为我做：

void setLoader(boolean T, String msg){
    View LAY = findViewById(R.id.loaderLayout);
    TextView MTV = (TextView) findViewById(R.id.loader_msg);
    if(T && !loaderStarted){
        loader.start();
        LAY.setVisibility(View.VISIBLE);
        MTV.setText(msg);
        loaderStarted = true;
    }
    else if (!T && loaderStarted) {
        loader.interrupt();
        LAY.setVisibility(View.GONE);
        loaderStarted = false;
    }
}

然后我需要获得用户和传递，然后再次使用该线程锁定UI以检查用户和传递问题是：我有问题暂停一个线程：| 我的主要编程语言不是java

所以请帮助我，我有这样的线程：

//first make loading icon visible then call :

    final private Thread loader = new Thread(new Runnable(){

    @Override
    public void run() {
        int i = 0;
        while (true){
            if(loader.isInterrupted()){
                return;
                }
            try {Thread.sleep(25);} catch (InterruptedException e) {}
            final int j = i;
            runOnUiThread(new Runnable(){
                public void run() {
                    ImageView imageView = (ImageView) findViewById(R.id.loaderImage);
                    Matrix matrix = new Matrix();
                    imageView.setScaleType(ScaleType.MATRIX);
                    int newWIDTH = imageView.getWidth();
                    int newHIEGHT = imageView.getHeight();
                    matrix.postScale(((float)(newWIDTH))/imageView.getDrawable().getBounds().width(), ((float)(newHIEGHT))/imageView.getDrawable().getBounds().height());
                    matrix.postRotate((float) j, newWIDTH/2, newHIEGHT/2);
                    imageView.setImageMatrix(matrix);
                }   
            });
            i = (i + 15) % 360;
        }
    }
});

然后我需要一个像这样的方法：

void setLoader(boolean T, String msg){
    View LAY = findViewById(R.id.loaderLayout);
    TextView MTV = (TextView) findViewById(R.id.loader_msg);
    if(T && !loaderStarted){
        loader.start();
        LAY.setVisibility(View.VISIBLE);
        MTV.setText(msg);
        loaderStarted = true;
    }
    else if(T && loaderSuspended && loaderStarted){
        loader.resume();
        LAY.setVisibility(View.VISIBLE);
        MTV.setText(msg);
        loaderSuspended = false;
    }
    else if (loaderStarted && !loaderSuspended) {
        loader.suspend();
        LAY.setVisibility(View.GONE);
        loaderStarted = false;
        loaderSuspended = true;
    }
}

暂停线程然后恢复它（.suspend（）和.resume（）已弃用）

提前致谢:) 抱歉可怕的英语（：D）

Answer 1

您可以尝试添加字段：

// defines the paused state
private volatile boolean isPaused = false;

// a monitor object for wait/notify pattern
private final Object suspender = new Object();

然后在你的逻辑中：

void pause(){
     synchronized(suspender){
         isPaused = true;        
     }
}

void resume(){
     synchronized(suspender){
         isPaused = false;
         suspender.notify();
     }
}

while (true){
    if(loader.isInterrupted()){
        return;
    }

    // this outside loop is needed to deal with spurious wakeup
    synchronized (suspender){
        while(isPaused){            
            suspender.wait();
        }
    }

    ...
}

有关等待和通知的更多信息：A simple scenario using wait() and notify() in java

Answer 2

最好在Thread实现中引入布尔标志：

final private volatile boolean isSuspended = false;

然后您可以将此标记设置为true / false，并在run方法中重写暂停逻辑，如下所示：

while (true) {
    while (isSuspended) {
        try {Thread.sleep(25);} catch (InterruptedException e) {}
    }
    ...
}

线程：启动，暂停，恢复

2 个答案: