帮助我填充数组Final[]
,使数组Even[]
的值存储在Final[]
&的偶数索引上数组Odd[]
填充Final[]
个奇数索引..
public class Test
{
public static void main(String[] args)
{
A obj = new A();
obj.run();
}
}
class A
{
int temp, b;
public void run(){
Double[] ResultList = {1.1,2.2,3.33,4.1,5.0,6.7777}; //Dummy Values
Double[] Final = new Double[ResultList.length];
Double[] Even = {11.989898,22.545454,33.5454,44.444,55.5647,66.11111}; //Dummy Values
Double[] Odd = {11.545454,22.5454,33.444,44.5647,55.989898,66.11111}; //Dummy Values
for(int a = 0; a < ResultList.length ; a+=2)
{
if(temp != 0)
{
b = temp;
System.out.println("Outer Temp B: "+temp+"\n");
}
for(b = 0; b <= a; b++) //Want to stop this loop in a Manner That b=0,1,2,3,4...
{
temp = b;
System.out.println("Inner Temp: "+b+"\n");
Final[a] = Even[b];
Final[a+1] = Odd[b];
if(b != 0) //Trying this to stop thsi loop from repetition
{
b = a+1;
System.out.println("Inner B: "+b+"\n");
}
}
}
for(int i = 0; i < ResultList.length; i++)
System.out.print(Final[i]+" ");
}
}
需要输出:{11.989898, 11.545454, 22.545454, 22.5454, 33.5454, 33.444, 44.444, 44.5647, 55.5647, 55.989898, 66.11111, 66.11111}
答案 0 :(得分:3)
我将如何做到这一点 -
public class A {
int temp, b;
public void run() {
double[] even = { 11.989898, 22.545454, 33.5454,
44.444, 55.5647, 66.11111 }; // Dummy Values
double[] odd = { 11.545454, 22.5454, 33.444,
44.5647, 55.989898, 66.11111 }; // Dummy Values
double[] out = new double[even.length
+ odd.length];
int count = 0;
for (int i = 0; i < out.length; i += 2) {
out[i] = even[count];
out[i + 1] = odd[count];
count++;
}
for (int i = 0; i < out.length; i++) {
System.out.print(out[i] + " ");
}
}
public static void main(String[] args) {
A obj = new A();
obj.run();
}
}
哪个输出
11.989898 11.545454 22.545454 22.5454 33.5454 33.444 44.444 44.5647 55.5647 55.989898 66.11111 66.11111
答案 1 :(得分:2)
你走了:
Double Final[] = new Double[Even.length + Odd.length];
for (int i = 0; i < Even.length; ++i)
Final[i*2] = Even[i]; // i*2 --> 0, 2, 4
for (int i = 0; i < Odd.length; ++i)
Final[i*2+1] = Odd[i]; // i*2+1 --> 1, 3, 5