用两个数组填充php中的数组

Question

我有两个数字数组（这些数组总是具有相同数量的键和值）。

$array1 = array(0 => "key1", 1 => "key2");
$array2 = array(0 => "value1", 1 => "value2");
$array_final = array(value of the $array1 => $value of the array2);

如果我写了一段时间并填写$array_final，它只会填写最后一个键和值

所以就像：

for ($i = 0; $i < count($array(1))
{
    $array_final = array($array1[$i] => $array2[$i]);
}
$array_final = array("key2" => "value2");

但我想：

$array_final = array("key1" => "value1", "key2" => "value2");

Answer 1

您需要array_combine

它完全符合您的需要

所以基本上

$array1 = array(0 => "key1", 1 => "key2");
$array2 = array(0 => "value1", 1 => "value2");

$array_final = array_combine($array1, $array2);

Answer 2

for ($i=0; $i< sizeof($array1) &&  $i< sizeof($array2) ; $i++)
{
  $array_final[$array1[$i]] =$array2[$i];
}

Answer 3

您可以尝试以下代码。

       $array1 = array(0 => "key1", 1 => "key2");
       $array2 = array(0 => "value1", 1 => "value2");
       $array_final = combine_if_same_keys($array1,$array2);
       print_r($array_final);


       function combine_if_same_keys( $array_one, $array_two ) {

         $expected = false;

          ksort($array_one);
          ksort($array_two);

         $diff = array_diff_key($array_one, $array_two);
         if( empty($diff) && count($array_one) == count($array_two) ) {
             $expected = array_combine( $array_one, $array_two );
         }

          return $expected;
       }