std :: bind与模板成员函数

时间:2013-12-20 11:07:46

标签: templates c++11 std-function stdbind function-binding

我有一个奇怪的问题,我无法绑定此模板成员函数, 所有这些代码都编译成:http://ideone.com/wl5hS8

这是一个简单的代码:我有一个ExecutionList,它应该在std::vector中保存可调用的函数。我现在可以通过调用ExecutionList::addFunctor来添加函数。但在那里,我无法绑定template<typename T> void Functor::calculate(T * t)。我问我为什么,这里缺少什么,编译器不能以某种方式推断出我在

中写的内容
m_calculationList.push_back( std::bind(&T::calculate<Type>, extForce, std::placeholders::_1 ) );

* 错误:*

error: expected primary-expression before ‘>’ token
                 m_calculationList.push_back( std::bind(T::calculate<Type>, extForce, std::placeholders::_1 ) );
                                                                     ^

守则:

#include <functional>
#include <iostream>
#include <vector>

struct MyType{
    static int a;
    int m_a;
    MyType(){a++; m_a = a;}

    void print(){
        std::cout << "MyType: " << a << std::endl;
    }
};
int MyType::a=0;


struct Functor{

    static int a;
    int m_a;

    Functor(){a++; m_a = a;}

    // Binding this function does not work 
    template<typename T>
    void calculate(T * t){}

    // Binding this function works!!!
    void calculate2(MyType * t){
        std::cout << " Functor: " << m_a <<std::endl;
        t->print();
    }

};

int Functor::a=0;

// Binding this function works!!!
template<typename T>
void foo( T * t){}

class ExecutionList{
    public:
        typedef MyType Type;

        template<typename T>
        void addFunctor(T * extForce){
            //m_calculationList.push_back( std::bind(&T::calculate<Type>, extForce, std::placeholders::_1 ) );   /// THIS DOES NOT WORK
            m_calculationList.push_back( std::bind(&T::calculate2, extForce, std::placeholders::_1 ) );
            m_calculationList.push_back( std::bind(&foo<Type>, std::placeholders::_1 ) );
        }


        void calculate(Type * t){
            for(auto it = m_calculationList.begin(); it != m_calculationList.end();it++){
                (*it)(t); // Apply calculation function!
            }
        }

    private:
        std::vector< std::function<void (Type *)> > m_calculationList;
};



int main(){
    MyType b;
    ExecutionList list;
    list.addFunctor(new Functor());
    list.addFunctor(new Functor());
    list.calculate(&b);
}

1 个答案:

答案 0 :(得分:3)

您似乎错过了模板关键字。如果T是模板参数而T :: calculate是指模板,则需要告诉编译器计算是模板而不是某些静态变量,您尝试使用less-than运算符与其他东西进行比较:

T::template calculate<Type>

几年前我遇到了完全相同的问题,但今天(发布在C ++ 11之后)我可能会用一个更简单的lambda解决它:

std::function<void(Type*)> func = [obj](Type*param){obj.calculate(param);};

无论如何,尽量减少new次使用的次数。寻找更好的方法来管理您的资源。您的代码似乎泄漏了几个仿函数。