Question

a = 4.0
b = 3.0
c = 2.0
d = 1.0
f = 0.0
counter = 0
gpa = 0
while True:
    grade = input("what is your grade ")
    if(grade == "A" or "a"):
        counter += 1
        gpa += a
    elif(grade == "B" or "b"):
        counter += 1
        gpa += b
    elif(grade == "C" or "c"):
        counter += 1
        gpa += c
    elif(grade == "D" or "d"):
        counter += 1
        gpa += d
    elif(grade == "F" or "f"):
        counter += 1
        gpa += f
    elif (grade == ""):
        finalgrade = (gpa/counter)
        print(finalgrade)
        break
    else:
        print ("invalid input")

所以我一直在尝试这项工作，但无论我做什么，我都无法弄清楚...... 当我使用调试器时，它没有多大帮助，但它说它正好超过了所有的elif语句

Answer 1

此：

if grade == "A" or "a"

不是真的按照你的想法去做。由于python中的运算符优先级，它计算grade=="A"，然后计算or到"a"。这将始终评估为True。

请改用in运算符：

if grade in ("A", "a"):

或者，甚至更好：

if grade.lower() == "a":

Answer 2

而不是

grade == "A" or "a" #always True, since "a" is truthy

使用

grade == "A" or grade == "a"

或

grade.upper() == "A"

同样更改其他陈述。

虽然我会这样做

 import itertools

 points = {'A':4, 'B':3, 'C':2, 'D':1, 'F':0}

 total = 0.
 for count in itertools.count():
     grade = input('What is your grade ')
     if not grade:
         break
     try:
         total += points[grade]
     except KeyError:
         print('invalid input')
 print(total / count)

Gpa计算器错误无法修复

2 个答案: