更新,添加评论中的问题:
将Map映射到Map的最佳方法是什么 Foo是一个Enum。从概念上讲,它看起来非常复杂 不是一个复杂的想法。
此代码起作用,它是简单MUD client的一部分。基本思想是Monitor
保存数据(生命点等),这些数据将在游戏过程中显示给用户,可能是在辅助JPanel
中;这些方面的东西。此报告的可能值位于Attribs
Enum
。
在走太远之前,当我查看Monitor
类以及创建单个实例所需的内容时,它似乎有点冗长。
如果我将convertToEnumEntry
移出Monitor
,那么该课程将无效。所以,班级不能变小,我不认为。是否有我可以使用的模式(或使用更好)?
此类中的所有内容都基于以下假设:如果convertToEnumEntry
返回对Map.Entry
的空引用,然后获取一个不适合{{1}的特定String
}}:
Attribs
与其他键不同,敌人可以是任何enemy = stringEntry.getKey();
。其他键仅限于String
(属性)的Enum
值。
Attribs
将所有内容都塞进一个类来解析和构建public class Monitor {
private static Logger log = Logger.getLogger(Monitor.class.getName());
private Map<Attribs, Ratio> mapOfAttributes = new HashMap<>();
private String enemy = null;
private Monitor() {
}
public Monitor(Map<String, Ratio> mapStringToRatio) {
init(mapStringToRatio);
}
private void init(Map<String, Ratio> mapStringToRatio) {
SimpleEntry<Attribs, Ratio> attribsEntry = null;
for (Entry<String, Ratio> stringEntry : mapStringToRatio.entrySet()) {
attribsEntry = null;
attribsEntry = convertToEnumEntry(stringEntry);
if (attribsEntry != null) {
mapOfAttributes.put(attribsEntry.getKey(), attribsEntry.getValue());
} else {
enemy = stringEntry.getKey(); //assumes key is enemy value
mapOfAttributes.put(Attribs.ENEMY, stringEntry.getValue());
}
}
}
private SimpleEntry<Attribs, Ratio> convertToEnumEntry(Entry<String, Ratio> stringEntry) {
Ratio ratio = stringEntry.getValue();
SimpleEntry<Attribs, Ratio> attribEntry = null;
for (Attribs attribute : Attribs.values()) {
if (stringEntry.getKey().equalsIgnoreCase(attribute.name())) {
attribEntry = new HashMap.SimpleEntry<>(attribute, ratio);
}
}
return attribEntry;
}
@Override
public String toString() {
StringBuilder sb = new StringBuilder();
sb.append("\nfighting\t\t" + enemy + "\n");
for (Map.Entry<Attribs, Ratio> e : mapOfAttributes.entrySet()) {
sb.append("\n");
sb.append(e.getKey().name());
sb.append("\t");
sb.append(e.getValue().toString());
}
sb.append("\n");
return sb.toString();
}
}
,或将所有内容放入Map
中是很诱人的。目前,Monitor
是一种中间立场,因为它完成了大部分艰苦工作,但并不能完全建立一个完整的RegexMapBuilder
:
Monitor
为简洁起见,我省略了public class RegexMapBuilder {
public static Map<String, Ratio> stringToRatiosMap(String input) {
Map<String, Ratio> mapOfStringsToRatios = new HashMap<>();
Map<String, String> strings = stringMap(input);
Pattern fraction = Pattern.compile("(\\d+)/(\\d+)");
Pattern wholeNumber = Pattern.compile("(\\d+)");
Pattern percent = Pattern.compile("(\\d+)%");
Matcher matcher;
int numerator, denominator;
Ratio ratio = null; //need numerator and denominator values
for (Entry<String, String> e : strings.entrySet()) {
matcher = wholeNumber.matcher(e.getValue());
while (matcher.find()) {
numerator = Integer.parseInt(matcher.group(1));
denominator = 1;
ratio = new Ratio(numerator, denominator);
}
matcher = fraction.matcher(e.getValue());
while (matcher.find()) {
numerator = Integer.parseInt(matcher.group(1));
denominator = Integer.parseInt(matcher.group(2));
ratio = new Ratio(numerator, denominator);
}
matcher = percent.matcher(e.getValue());
while (matcher.find()) {
numerator = Integer.parseInt(matcher.group(1));
denominator = 100;
ratio = new Ratio(numerator, denominator);
}
mapOfStringsToRatios.put(e.getKey(), ratio);
}
return mapOfStringsToRatios;
}
private static Map<String, String> stringMap(String input) {
Map<String, String> strings = new HashMap<>();
Pattern pattern = Pattern.compile("(\\w+): +(\\S+)");
Matcher matcher = pattern.matcher(input);
while (matcher.find()) {
strings.put(matcher.group(1), matcher.group(2));
}
return strings;
}
}
,但Enum
只是此报告打印的一些属性的列表。唯一棘手的部分是有一个值实际上不是Enum类型。