Question

我有一些像这样的清单：

[['CD', 'CC', 'CD'], 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1]
[['DT', 'CC', 'CD'], 0, 0, 1, 0, 1, 0, 1, 1, 1, 1, 1, 1] 
[['EX', 'CC', 'CD'], 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0] 
[['JJ', 'CC', 'CD'], 0, 0, 1, 0, 1, 0, 1, 1, 0, 1, 1, 1]

我希望将这些列表明确地写入csv文件列。到目前为止我做了什么：

for i in range(1,840):
    # function which compute the result value
    result=Count_SP(i,leng_second,first_position+1,second_position)
    final.append(result)


print final             # final contains lists      
File_Write(final)       # File_Write() writes the final into a csv file

需要输出：

['CD', 'CC', 'CD'],['DT', 'CC', 'CD'],['EX', 'CC', 'CD'],['JJ', 'CC', 'CD']
1,0,0,0
1,0,0,0
1,1,0,1
1,0,0,0
1,1,0,1
1,0,0,0
1,1,0,1
1,1,0,1
1,1,0,0
1,1,0,1
1,1,0,1
1,1,0,1

Answer 1

如果您将列表放在容器中，那么实际上非常简单：

import csv

container = [[['CD', 'CC', 'CD'], 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1],
             [['DT', 'CC', 'CD'], 0, 0, 1, 0, 1, 0, 1, 1, 1, 1, 1, 1],
             [['EX', 'CC', 'CD'], 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
             [['JJ', 'CC', 'CD'], 0, 0, 1, 0, 1, 0, 1, 1, 0, 1, 1, 1]]

with open('out.csv', 'w') as csvfile:
    csvw = csv.writer(csvfile, delimiter=',')
    for column in zip(*[s for s in container]):
        csvw.writerow(column)

这将创建文件out.csv，该列将包含输入列表：

"['CD', 'CC', 'CD']","['DT', 'CC', 'CD']","['EX', 'CC', 'CD']","['JJ', 'CC', 'CD']"
1,0,0,0
1,0,0,0
1,1,0,1
1,0,0,0
1,1,0,1
1,0,0,0
1,1,0,1
1,1,0,1
1,1,0,0
1,1,0,1
1,1,0,1
1,1,0,1

将嵌套列表逐列写入CSV

1 个答案: