只使用Grok讲座

Question

某些背景信息：

我从未尝试过在3天前编程任何东西，所以我是一个完全的初学者。我正在尝试学习python，我正在通过一个关于Grok学习的免费模块学习https://groklearning.com/courses/有一个问题的答案我已经大部分已经弄清楚但是无法完成。该模块是一个入门课程，所以我相信有一个相当简单的解决方案，但我见过的类似情况的一切都在我的头上。

问题是：＆＃34;机器人在一条线上！

机器人正在入侵（你的书面作品）！机器人潜入你的文本文件。编写一个程序，读取用户的一行文本，并打印出文本行中是否有机器人。

如果机器人中的所有小写字母都出现机器人，则打印出来：行中有一个小机器人。

如果单词ROBOT出现在行中的全部大写字母中，则打印出来：行中有一个大机器人。

如果机器人出现在大写和小写字母的任意组合的行中，则打印出来：行中有一个中等大小的机器人。 否则，如果这些条件均不成立，则应打印出：此处没有机器人。你的程序应该像这样工作：

Line: I'm baking chocolate robot brownies.
There is a small robot in the line.

这是另一个例子：

Line: Look at the rOBOt down the road.
There is a medium sized robot in the line.

如果字母机器人出现在该行中，但作为更大词的一部分，则不应报告找到的任何机器人。＆＃34;

Line: There's a strobotron at the concert.
No robots here.

到目前为止我的解决方案：

line = input("Write something:")
lr = ("There is a small robot in the line.")
br = ("There is a big robot in the line.")
mr = ("There is a medium sized robot in the line.")
nr = ("No robots here.")
check1 = ("robot" in line)
check2 = ("ROBOT" in line)
lowcase = check1
upcase = check2
if(lowcase == True):
  print(lr)
elif(upcase == True):
  print(br)
else:
  print(nr)

请记住我是一个完全的初学者，所以你的解决方案可能需要一些解释，并且可以随意批评我已编写的代码，但到目前为止它似乎有用。感谢您花时间阅读所有这些并提供帮助。

Answer 1

如何使用str.lower或str.casefold：

>>> 'Look at the rOBOt down the road.'.lower()
'look at the robot down the road.'

>>> 'robot' in 'Look at the rOBOt down the road.' # check1
False
>>> 'ROBOT' in 'Look at the rOBOt down the road.' # check2
False
>>> 'robot' in 'Look at the rOBOt down the road.'.lower()
True

if lowcase:
    print(lr)
elif upcase:
    print(br)
elif 'robot' in line.lower():
    print(mr)
else:
    print(nr)

Answer 2

最困难的部分是当机器人出现在一个更大的单词的一部分时，因为很容易在字符串中查找“机器人”，但更难以检查它的两侧是否有边界。

仅使用内置：

BOUNDARIES = " .,?!:;'\""

while True:
    string = input("Write something or hit Enter to quit: ")
    # This breaks the loop (quits the program) if the user hit
    # an Enter.
    if not string:
        break
    # First we look robot in the lowercased string.
    part = string.lower().partition("robot")
    # If a robot is in the string, the middle part of part
    # is going to be "robot". If not, it is an empty string.
    if not part[1]:
        print("No robots here.")
    # If the end of part[0] and the beginning of part[2] is
    # not in BOUNDARIES then we still have no robots there.
    elif ((not part[0] or not part[0][-1] in BOUNDARIES)
        and (not part[2] or not part[2][0] in BOUNDARIES)):
        print("No robots here.")
    # Now we look for small and big robots in the original
    # string.
    elif "robot" in string:
        print("There is a small robot in the line.")
    elif "ROBOT" in string:
        print("There is a big robot in the line.")
    # If we are here that is because of a medium robot.
    else:
        print("There is a medium sized robot in the line.")

使用regular expressions使其变得更短/更清洁。但是，您的程序启动会慢一点，因为它需要先导入re模块：

import re
PATTERN = r"\b[rR][oO][bB][oO][tT]\b"

while True:
    string = input("Write something or hit Enter to quit: ")
    if not string:
        break
    search = re.search(PATTERN, string)
    if not search:
        print("No robots here.")
    elif search.group() == "robot":
        print("There is a small robot in the line.")
    elif search.group() == "ROBOT":
        print("There is a big robot in the line.")
    else:
        print("There is a medium sized robot in the line.")

试运行：

Write something or hit Enter to quit: I'm baking chocolate robot brownies.
There is a small robot in the line.
Write something or hit Enter to quit: Look at the rOBOt down the road.
There is a medium sized robot in the line.
Write something or hit Enter to quit: There's a strobotron at the concert.
No robots here.
Write something or hit Enter to quit: I have a robot.
There is a small robot in the line.
Write something or hit Enter to quit: The code on it's plate was: "ROBOT 142/1".
There is a big robot in the line.
Write something or hit Enter to quit:

Answer 3

这是一种方法。只需使用他们在课程中教给你的东西。我知道它不是最聪明的方式，但它简单而且有效！：）

# Enter your code for "Robots in a line!" here.
str1 = input('Line: ')
words = str1.split()
if 'ROBOT' in words:
  print('There is a big robot in the line.')
elif 'robot' in words:
  print('There is a small robot in the line.')
elif 'robot' in str1.lower().split():
  print('There is a medium sized robot in the line.')
else:
  print('No robots here.')

Answer 4

您可以尝试如下，但这涉及多次检查。

s = "I'm baking chocolate roBOT brownies"
lower_text = 'robot'

normal_split = s.split()
lower_split = s.lower().split() 

if lower_text in normal_split:
    # check if lower case robot is present in normal split
    print('There is a small robot in the line.')
elif lower_text.upper() in normal_split:
    # check if upper case robot is present in normal split
    print('There is a big robot in the line.')
elif lower_text not in lower_split:
    # check if atleast any case robot is present in the split
    print('No robots here.')
else:
    # if none of the above matches then medium size robot
    print('There is a medium sized robot in the line.')

干杯！

Answer 5

只使用Grok讲座

line = input("Line: ")
line1 = line.lower() #mixed case will be converted to lowercase
line = line.split() 
line1 = line1.split() #split line1 to see if the word robot exists

if "robot" in line:
    print("There is a small robot in the line.")
elif "ROBOT" in line:
    print("There is a big robot in the line.")
elif "robot" and "ROBOT" not in line and "robot" not in line1: #checking if lower case, upper case, and mixed case converted robot exist
    print("No robots here.")
else:
    print("There is a medium sized robot in the line.")

Answer 6

您可以使用以下内容在Python字符串中找到大小写混合的单词：

str1 = input('Line: ')
words = str1.split()
if 'ROBOT' in words:
print('There is a big robot in the line.')
elif 'robot' in words:
print('There is a small robot in the line.')
elif 'robot' in str1.lower().split():
print('There is a medium sized robot in the line.')
else:
print('No robots here.')

在python字符串中查找混合大小写的单词

6 个答案:

只使用Grok讲座