Question

我正在研究项目中的问题。我有一个带有列的数据库，我存储了类型，如“15分钟休息”或“30分钟空闲时间” 我想用类别创建另一个列。我的类别存储在字典中：

{ "short":["10","5","15","10min","5min","15min","shorter"],
"middle":["20","25","30","35","20min","25min","30min","35min"],
"long":["40","45","50","55","60","40min","45min","50min","55min","60min"]}

任何想法如何使用python为类型分配类别？我的意思是那部分与字典中的单词相似？我的代码到目前为止

...calling sql select
for i, index in rows():
    type = index[0]
    if (any of words from dictionary) is in type:
        category = (name of category, for example "short")
        update in sql
        ...

THx的

Answer 1

您想知道任何类别标记是否在中断描述中。假设s1和s2是您的示例说明，d是您的字典：

s1 = "15 mins break"
s2 = "30 min free time"
s3 = "something5something"

然后，下面的表达式将评估它们的类别（re.findall()的目的是标记文本;将正则表达式替换为适合您项目的任何类型。）

[cat for cat in d if any(marker in re.findall(r'[a-z0-9]+',s1) for marker in d[cat])]
#['short']

[cat for cat in d if any(marker in re.findall(r'[a-z0-9]+',s2) for marker in d[cat])]
#['middle']

[cat for cat in d if any(marker in re.findall(r'[a-z0-9]+',s3) for marker in d[cat])]
#[]

这假设所有字符串都是小写字母。

从字典中的字典中查找单词

1 个答案: