将R中的两个向量组合成一个未去除的NA

Question

我有两个xts对象：

buypoints
2010-04-20 7.096034  
2010-04-22 7.097276  
2010-06-02 7.001592  
2010-06-10 6.991030  
2010-07-09 6.982826  
2010-08-27 6.970345



sell points  
2010-04-16 7.083497  
2010-04-21 7.095015  
2010-04-27 7.076409  
2010-06-04 6.970617  
2010-06-24 6.978857  
2010-08-05 7.026258  
2010-09-27 7.040676  
2010-10-28 7.076468

我想合并这两个对象，以便我的最终输出如下：

2010-04-16 7.083497  
2010-04-20 7.096034   
2010-04-21 7.095015  
2010-04-22 7.097276   
2010-04-27 7.076409  
2010-06-02 7.001592   
2010-06-04 6.970617  
2010-06-10 6.991030    
2010-06-24 6.978857  
2010-07-09 6.982826    
2010-08-05 7.026258  
2010-08-27 6.970345    
2010-09-27 7.040676  
2010-10-28 7.076468

也就是说，来自两个对象的数据仅按one column的时间顺序排列。 请建议一种方法

Answer 1

您可以尝试以下方式：

rbind(buypoints, sellpoints)
# [,1]
# 2010-04-16 7.083497
# 2010-04-20 7.096034
# 2010-04-21 7.095015
# 2010-04-22 7.097276
# 2010-04-27 7.076409
# 2010-06-02 7.001592
# 2010-06-04 6.970617
# 2010-06-10 6.991030
# 2010-06-24 6.978857
# 2010-07-09 6.982826
# 2010-08-05 7.026258
# 2010-08-27 6.970345
# 2010-09-27 7.040676
# 2010-10-28 7.076468
# > class(rbind(buypoints, sellpoints))
# [1] "xts" "zoo"

看起来xts已经预见到了按日期排序的需要，从而避免了任何明确的排序函数。非常整洁，嗯？