Question

我有一个返回字符串的过程，如下所示

<USAGESTARTT=1387847400,USAGEENDT=1387849200,EVENTCOUNT=8,EVENTDURATION=247996,DISKSPACEUSED=0,BANDWIDTHOUT=0,BANDWIDTHCDN=0,HOURSUSED=0,AMOUNT=41332.66,RECYCLED_AMOUNT=0,NUM_RECYCLED_CDR=0,PROCESS_NAME=CP_RAX_RAT_SUSP,SERVICE_TYPE=CLOUD_BKUP>,<USAGESTARTT=0,USAGEENDT=1386032400,EVENTCOUNT=8,EVENTDURATION=74262,DISKSPACEUSED=0,BANDWIDTHOUT=0,BANDWIDTHCDN=0,HOURSUSED=0,AMOUNT=99.02,RECYCLED_AMOUNT=0,NUM_RECYCLED_CDR=0,PROCESS_NAME=CP_RAX_RAT_SUSP,SERVICE_TYPE=CLOUD_SRVR_UPTIME>,

这实际上是一组两行数据集相互连接在一起。单独看起来像

字符串1

<USAGESTARTT=1387847400,USAGEENDT=1387849200,EVENTCOUNT=8,EVENTDURATION=247996,DISKSPACEUSED=0,BANDWIDTHOUT=0,BANDWIDTHCDN=0,HOURSUSED=0,AMOUNT=41332.66,RECYCLED_AMOUNT=0,NUM_RECYCLED_CDR=0,PROCESS_NAME=CP_RAX_RAT_SUSP,SERVICE_TYPE=CLOUD_BKUP>,

String 2

<USAGESTARTT=0,USAGEENDT=1386032400,EVENTCOUNT=8,EVENTDURATION=74262,DISKSPACEUSED=0,BANDWIDTHOUT=0,BANDWIDTHCDN=0,HOURSUSED=0,AMOUNT=99.02,RECYCLED_AMOUNT=0,NUM_RECYCLED_CDR=0,PROCESS_NAME=CP_RAX_RAT_SUSP,SERVICE_TYPE=CLOUD_SRVR_UPTIME>,

我的要求是我想先将这个字符串拆分成不同的行，然后将每一行拆分成多列，其中'='前面的字符串是列名，'='后面的字符串是需要插入的值进入专栏。例如： - 在字符串'USAGESTARTT = 0'中，USAGESTARTT是列名，0是USAGESTARTT列中的值。此示例仅显示两行，但我的过程可以返回多个彼此连接的行。

您能否建议解决此要求？

Answer 1

我用这个TVF分割字符串：

CREATE function dbo.split (@value varchar(8000),@delim varchar(8000))
returns table
as
return
(
select d.value,
       d.orders,
       ivalue = convert(int, case when isnumeric(d.value)=1 and d.value not like '%[^0-9 +-]%' and len(replace(replace(replace(d.value,' ',''),'-',''),'+',''))<=10 then case when convert(bigint,d.value) between -2147483648 and 2147483647 then d.value end end)

    from
        (
            select   
                    value= replace(substring(value,
                                            idx,
                                            case when cnt>=0 then cnt end 
                                         )
                                 ,char(1),'')
                    ,orders=( datalength(left(value,idx-1))-datalength(replace(left(value,idx-1),@delim,''))
                            )/datalength(@delim)
                from (
                       select number
                             ,idx
                             ,cnt = charindex(@delim,value, number + 1) - number - datalength(@delim)
                             ,value 
                          from 
                                (
                                   select number
                                         ,idx = number + datalength(@delim)
                                         ,value = (select @delim+char(1)+@value+char(1)+@delim)
                                      from dbo.s_value
                                        where number between 1 and datalength( (select @delim+char(1)+@value+char(1)+@delim) ) - datalength(@delim)

                                ) t            
                          where substring(t.value, number, datalength(@delim)) = @delim         
                     ) t             
       ) d          
)

GO

以这种方式使用：

select * from dbo.split(@YOUR_STRING,'>,<')

Answer 2

如果您使用的是SQL Server，可以将字符串放在XML类型的变量中，然后解析此XML，请参阅Parse XML in SQL Server以获取示例。

如何将字符串拆分为多个列，然后拆分为多个行

2 个答案: