我想第二个'Enter'按钮允许用户退出此窗口。命令是什么?我相信self.quit会退出一切,但我使用的命令不起作用。
import tkinter as tk
class Enter_Name_Window(tk.Toplevel):
'''A simple instruction window'''
def __init__(self, parent):
tk.Toplevel.__init__(self, parent)
self.text = tk.Label(self, width=40, height=2, text= "Please enter your name and class." )
self.text.pack(side="top", fill="both", expand=True)
enter_name = Entry(self)
enter_name.pack()
enter_name.focus_set()
def callback():
self.display_name = tk.Label(self, width=40, height=2, text = "Now please enter your tutor group.")
self.display_name.pack(side="top", fill="both", expand=True)
tutor = Entry(self)
tutor.pack()
tutor.focus_set()
Enter_0.config(state="disabled")
Enter_0_2 = Button(self, text="Enter", width=10, command=Enter_Name_Window.quit)
Enter_0_2.pack()
Enter_0 = Button(self, text="Enter", width=10, command=callback)
Enter_0.pack()
答案 0 :(得分:1)
开始时有很多错误,最值得注意的是:
command=Enter_Name_Window.quit
应该是
command=self.destroy
避免使用quit()
方法作为其unstable,并传递类实例self
而不是新的类对象
这里的任何地方都是您修改后的代码:
class Enter_Name_Window(tk.Toplevel):
'''A simple instruction window'''
def __init__(self, parent):
tk.Toplevel.__init__(self, parent)
self.parent = parent
self.text = tk.Label(self.parent, width=40, height=2, text= "Please enter your name and class." )
self.text.pack(side="top", fill="both", expand=True)
enter_name = tk.Entry(self)
enter_name.pack()
enter_name.focus_set()
def callback():
self.display_name = tk.Label(self.parent, width=40, height=2, text = "Now please enter your tutor group.")
self.display_name.pack(side="top", fill="both", expand=True)
tutor = tk.Entry(self.parent)
tutor.pack()
tutor.focus_set()
Enter_0.config(state="disabled")
Enter_0_2 = tk.Button(self.parent, text="Enter", width=10, command=self.destroy)
Enter_0_2.pack()
Enter_0 = tk.Button(self.parent, text="Enter", width=10, command=callback)
Enter_0.pack()