Question

我编写了一个代码来使用for循环完成一个完美的三部曲。我如何使用更多for循环来创建这些三部曲中的三部曲？

注意：“ROptionPane”与“JOptionPane”相同

public static void main(String[] args) {


    String rowsWantedAsSt = ROptionPane.showInputDialog(null, "How big would you like the Diamond to be?",
            "Diamond", ROptionPane.QUESTION_MESSAGE);

    int rowsWanted = Integer.parseInt(rowsWantedAsSt);


    //stars on the top row
    int starsWanted = 1;
    //spaces on the top row
    int spacesWanted = (rowsWanted * 2) + 3;





    for (int rows = 0; rows < rowsWanted; rows++) {
            for (int spaces = 0; spaces < spacesWanted; spaces++) {
                System.out.print(" ");
            }
            for (int stars = 0; stars < starsWanted; stars++) {
                System.out.print("*");
            }
            System.out.println();
            starsWanted += 2;
            spacesWanted--;
    }
            starsWanted = 1;

            spacesWanted = rowsWanted + 1;

        for (int rows = 0; rows < rowsWanted; rows++) {
            for (int spaces = 0; spaces < spacesWanted + 2; spaces++) {
                System.out.print(" ");
            }
            for (int stars = 0; stars < starsWanted; stars++) {
                System.out.print("*");
            }

            for (double spaces = 0; spaces < (spacesWanted * 2) - 3; spaces++) {
                System.out.print(" ");
            }
            for (int stars = 0; stars < starsWanted; stars++) {
                System.out.print("*");
            }
            System.out.println();
            starsWanted += 2;
            spacesWanted--;

        }      
    }
}

Answer 1

Triforce与创建Sierpinski triangle的算法的第一次迭代结果相同。由Triforces组成的Triforce看起来像算法的第二次迭代。

Rosettacode.org有两个不同的Java implementations函数，它将迭代生成一个ASCII Sierpinski三角形;你可能想从那里开始。

用Triforces制作Triforce？

1 个答案: