Question

我想为响应添加值。但响应采用这种格式

   {
  "participants": [
                    {
                      "lat_long": "0.0,0.0", 
                      "name": "alma" 
                     }
                  ],
  "lat_long": "0.0,0.0",
  "_id": "52a80a5dccb8137326000027"
  }

如何为键名添加值＆amp; lat_long。我正在使用Sbjson方法。

提前致谢。

Answer 1

NSURL * url=[NSURL URLWithString:@"Give your URL Here"];

    NSData * data=[NSData dataWithContentsOfURL:url];

    NSError * error;

    NSMutableDictionary * jsonDic=[NSJSONSerialization JSONObjectWithData:data options:NSJSONReadingMutableLeaves error:&error];


    NSLog(@"%@",jsonDic);


    NSMutableArray * jsonArray=jsonDic[@"participants"];

    NSLog(@"%@",jsonArray);

    NSString * str =[jsonArray valueForKey:@"lat_long"];


    NSString *  str1 =[jsonArray valueForKey:@"name"];

    NSLog(@"%@",str);

    NSLog(@"%@",str1);

试试这段代码。

Answer 2

我不确定，你在询问什么，但这可以帮助你获得Disctionary的钥匙。

 NSDictionary *json = [NSJSONSerialization .....//Parsed JSon
    NSMutableDictionary *arrCopy = [json mutableCopy];

   NSArray *keys= [json allKeys];
    for (NSString *keysV in keys){
        NSLog(@"Keys are %@", keysV);
        if ([keysV isEqualToString:@"_id"]) {
            [arrCopy setValue:@"121213211323" forKey:keysV];
        }else if (){

        }.......................
       }
    NSLog(@"After Value added: %@", arrCopy);

使用SBJson将值赋给json响应

2 个答案: