Question

我使用SBJSON来解析我的回复，总线不知何故我无法获取我的数据。我该如何解析这个被推迟的？

{"StatusCode":0,"Message":"email already exists","Content":{"HasApplication":false,"IsFaceBook":false,"UserActive":false,"UserAuthenticationType":0,"UserCredits":0,"UserDayAdded":0,"UserEmail":null,"UserEmailWasVerified":false,"UserGuid":null,"UserID":0,"UserSellerApproved":false,"UserTokef":0},"TotalCount":0}

我开始是这样的：

- (void)connection:(NSURLConnection *)connection didReceiveResponse:(NSURLResponse *)response 
{
    [responseData setLength:0];
    NSLog(@"%@",response); 
}

- (void)connection:(NSURLConnection *)connection didReceiveData:(NSData *)data 
{
    [responseData appendData:data];
    NSLog(@"Data recived");     
}

- (void)connection:(NSURLConnection *)connection didFailWithError:(NSError *)error 
{ 
    NSLog(@"Connection failed! Error - %@ %@",[error localizedDescription],
          [[error userInfo] objectForKey:NSURLErrorFailingURLStringErrorKey]);
    responseData = nil;

}

- (void)connectionDidFinishLoading:(NSURLConnection *)connection 
{
    NSLog(@"conenction loading finished"); 

    NSString *responseString = [[NSString alloc] initWithData:responseData encoding:NSUTF8StringEncoding];
    SBJsonParser *parser = [[SBJsonParser alloc] init];
    NSMutableDictionary *jsonDictionary = [parser objectWithString:responseString error:nil];
}

但接下来是什么？我需要StatusCode值和UserID。

Answer 1

你有一本词典，你可以使用它，例如：

NSMutableDictionary *jsonDictionary = [parser objectWithString:responseString error:nil];
NSNumber * statusCode = [jsonDictionary objectForKey:@"StatusCode"];
NSString * message = [jsonDictionary objectForKey:@"Message"];
NSDictionary * content = [jsonDictionary objectForKey:@"Content"];
// etc...

Answer 2

从JSON字符串的外观来看，您有一个包含三个键值对的词典，其中一个是具有多个键值对的另一个词典。因此，一旦将JSON responseString分配给NSMutableDictionary：

，就要处理它

应该是这样的：

NSNumber *statusCode = [jsonDictionary objectForKey:@"StatusCode"];
NSDictionary *contentDict = [jsonDictionary objectForKey@"Content"];
NSString *userID = [contentDict valueForKey@"UserID"];

完全不同的是，如果您要进行大量的网络服务互动，您可能需要认真审视AFNetworking。它会改变你的生活：）

另外，我不明白为什么你需要jsonDictionary作为NSMutableDictionary。除非您稍后更改它，否则使用NSDictionary，它的开销更小。

Answer 3

以及..... NSMutableDictionary *jsonDictionary = [parser objectWithString:responseString 也许它不是NSMutableDictionary，而是NSDictionary。然后：

NSString *statusCode = [jsonDictionary valueForKey:@"StatusCode"];
NSDictionary *contentDict = [jsonDictionary objectForKey@"Content"];
NSString *userID = [contentDict valueForKey@"UserID"];

在我的objective-c程序中解析json响应

3 个答案: