Question

在提示用户输入两个时间值后，我有一些问题以升序输出类（t1和t2）的两个对象。我知道bool和if结构的结构有一些错误。任何帮助将不胜感激！

bool lessthan(Time t2) //For two Time objects t1 and t2, t1.lessthan(t2) returns true if t1 is less than, or comes before t2.
{
    if (hours < t2.hours)
    {
        return true;
    }

    if (minutes < t2.minutes)
    {
        return true;
    }

    if (seconds < t2.seconds)
    {
        return true;
    }

    return false;
}


bool greaterthan(Time t2)  //For two Time objects t1 and t2, t1.greaterthan(t2) returns true if t1 is greater than, or comes after t2.
{
    if (hours > t2.hours)
    {
        return true;
    }

    if (minutes > t2.minutes)
    {
        return true;
    }

    if (seconds > t2.seconds)
    {
        return true;
    }

    return false;
}


bool equalto(Time t2) //For two Time objects t1 and t2, t1.equalto(t2) returns true if t1 is equal to, or is the same time as t2.
{
    if (hours == t2.hours)
    {
        return true;
    }

    if (minutes == t2.minutes)
    {
        return true;
    }

    if (seconds == t2.seconds)
    {
        return true;
    }

    return false;
}

在主要功能中，我有以下代码：

 cout << "\nTime values entered in ascending order: "<<endl;
        if (t1.lessthan(t2))
            t1.write();
        cout << endl;
            t2.write();
        cout << endl;

Answer 1

我认为同等级应该是

bool equalto(Time t2) //For two Time objects t1 and t2, t1.equalto(t2) returns true if t1 is equal to, or is the same time as t2.
{
    if (hours != t2.hours)
    {
        return false;
    }

    if (minutes != t2.minutes)
    {
        return false;
    }

    if (seconds != t2.seconds)
    {
        return false;
    }

    return true;
}

在你的代码中，如果小时数相同，就足够了，与分钟和秒无关。在我的版本中，我颠倒了逻辑顺序。

Answer 2

对于比较功能，请尝试：

bool equalto(Time t2) //For two Time objects t1 and t2, t1.equalto(t2) returns true if t1 is equal to, or is the same time as t2.
{
    if (hours == t2.hours && minutes == t2.minutes && seconds == t2.seconds)
    {
        return true;
    }

    return false;
}

bool lessthan(Time t2) //For two Time objects t1 and t2, t1.lessthan(t2) returns true if t1 is less than, or comes before t2.
{
    if (hours > t2.hours)
    {
        return false;
    }

    if (minutes > t2.minutes)
    {
        return false;
    }

    if (seconds > t2.seconds)
    {
        return false;
    }

    return true;
}

然后根据其他两个函数

实现greaterthan（）

greaterthan(Time t2)
{
    return (!(equalto(t2) || lessthan(t2));
}

另外，如果你想按升序输出时间，你需要做这样的事情：

cout << "\nTime values entered in ascending order: "<<endl;
if (t1.lessthan(t2))
{
    t1.write();
    cout << endl;
    t2.write();
    cout << endl;
}
else
{
    t2.write();
    cout << endl;
    t1.write();
    cout << endl;
}

使用当前代码，将始终执行最后3行，因为它们与if语句无关。你需要括号。

按升序输出两个时间值

2 个答案: